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anygoal [31]
3 years ago
14

Brighten is an expression that shows how to multiply 7 * 256 using expanded form and distributive property

Mathematics
1 answer:
charle [14.2K]3 years ago
4 0

I am not familiar with "brighten" but this is how you can expand and use the distributive property:

 7(256)

= 7(200 + 50 + 6)

= 7(200) + 7(50) + 7(6)

= 1400 + 350 + 30

= 1780

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The shape of the distribution of the time required to get an oil change at a 10 minute oil change facility is unknown. However,
lyudmila [28]

Answer:

The answer is below

Step-by-step explanation:

a) For a normal model the sample size has to be equal or greater than 30 so that it can be a normal distribution.

b) Given that:

μ = 11.2 minutes, σ = 4.8 minutes, n = 45

The z score determines how many standard deviations the raw score is above or below the mean. It is given by:

z=\frac{x-\mu}{\sigma} \\For\ a\ sample\ size(n)\\z=\frac{x-\mu}{\sigma/\sqrt{n} }

For x < 10 minutes

z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\ z=\frac{10-11.2}{4.8/\sqrt{45} }= -1.68

Therefore from the normal distribution table, P(x < 10) = P(z < -1.68) =  0.0465

7 0
3 years ago
Ella planted of the garden in the morning. She planted of the garden in the afternoon.
velikii [3]
There correct answer is B!
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How many inches represent 1 mile? Convert the map scale to a unit rate. 3/10in = 7/8mi
mote1985 [20]
I think it is 1357inchs

8 0
3 years ago
Solve the equation using addition or subtraction.
Dmitriy789 [7]
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5 0
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Read 2 more answers
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
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