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JulijaS [17]
3 years ago
9

A cone has a volume of 100

s="latex-formula"> Cubic units and a diameter of 10 units. What is the height of the cone?
Mathematics
1 answer:
Bumek [7]3 years ago
4 0

Answer:

12 units

Step-by-step explanation:

The formula for the volume of a cone is given as:

πr²h/3

The volume = 100π cubic units

Diameter = 10 units.

Radius = Diameter/2

= 10 units/2 = 5 units

Hence:

Formula to find the height of a cone

h = 3V/πr²

We substitute

h = 3 × 100π/π × 5²

h = 300π/25π

h = 12 units

The height = 12 units

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marysya [2.9K]

Answer:

a- 7 x 2 is a = 14

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4 0
3 years ago
When I add two to my number and then multiply it by five, I get thirty. What is my number?
rjkz [21]
30/5= 6
6 - 2 = 4
Your number is four
6 0
3 years ago
Read 2 more answers
9.48 as a mixed number in simplist form
mafiozo [28]

Answer:

<h2>9 12/25.</h2>

Step-by-step explanation:

9.48 as a mixed number in simplest form:

<em><u>948/100</u></em>

<em><u>948/100= 948 ÷ 4/100 ÷ 4</u></em>

<em><u>948/100= 948 ÷ 4/100 ÷ 4= 237/25</u></em>

<em><u>948/100= 948 ÷ 4/100 ÷ 4= 237/25= 9 12/25</u></em>

<u>9 12/25 is the mixed number.</u>

8 0
3 years ago
Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0
Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0

The general equation for the second-order polynomial is:

x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}

This condition must be observed for the case of a quadratic equation with equal roots:

4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0

k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0

k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0

3\cdot k^{3} - 3\cdot k - 1 = 0

7 0
3 years ago
Please help me with this math homework thanks :)
Ivenika [448]

Place a point at (0,-5) because that is the y-intercept (the -5 on the vertical line)

Since the slope is negative two which can be re-written as -2/1 (rise/run) you go down two and to the right once or up two and to the left once, it doesn't matter which. Another point can be placed at (1,-7) or (-3,-1), it still doesn't matter which.

Then you can draw a line connecting the two points.

I hope this helps :)

Let me know if you need further explanation

3 0
2 years ago
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