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Anastaziya [24]
3 years ago
11

Please solve this, will rate 5 stars and mark as STAR!​

Mathematics
1 answer:
Nina [5.8K]3 years ago
7 0

Answer:

\boxed{5 \cdot \sqrt{2}  \cdot \sqrt[6]{5} }

Step-by-step explanation:

\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}

\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}

\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

250=2 \cdot 5^3

\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5  \sqrt[3]{2}

Once

\sqrt[6]{2}  \cdot \sqrt[6]{5} = \sqrt[6]{10}

We have

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5}

We can proceed considering the common base of exponentials

\sqrt[3]{2}  \cdot \sqrt[6]{2}  =  2^{\frac{1}{3}} \cdot  2^{\frac{1}{6} }  = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}

Therefore,

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2}  \cdot \sqrt[6]{5}

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In the diagram,
forsale [732]

Answer:

Probability that the measure of a segment is greater than 3 = 0.6

Step-by-step explanation:

From the given attachment,

AB ≅ BC, AC ≅ CD and AD = 12

Therefore, AC ≅ CD = \frac{1}{2}(\text{AD})

                                  = 6 units

Since AC ≅ CD

AB + BC ≅ CD

2(AB) = 6

AB = 3 units

Now we have measurements of the segments as,

AB = BC = 3 units

AC = CD = 6 units

AD = 12 units

Total number of segments = 5

Length of segments more than 3 = 3

Probability to pick a segment measuring greater than 3,

= \frac{\text{Total number of segments measuring greater than 3}}{Total number of segments}

= \frac{3}{5}

= 0.6

4 0
3 years ago
The linear combination method is applied to a system of equations as shown.
olga_2 [115]
If you apply the linear combination method to the system like:
<span>4(.25x + .5y = 3.75) → x + 2y = 15
(4x – 8y = 12) → x – 2y = 3
2x = 18
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7 0
3 years ago
Read 2 more answers
Helpppp please ?????
BlackZzzverrR [31]
A) <DAE = 180-126 = 54
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8 0
3 years ago
professor wrote the following inequalities for N number of students in his lecture. N &lt;10, N&gt;10, N&lt;22, N&gt;22. Turns o
m_a_m_a [10]

Answer:

There are N students in the class.

We know that ONLY ONE of the inequalities is true:

N < 10

N > 10

N < 22

N > 22

We want only one of these four inequalities to be true.

Remember that if we have:

x > y

y is not a solution, because:

y > y is false.

Then:

If we take N = 10, then:

N < 22

Is the only true option.

While if we take N = 22

N > 10

is the only true option.

So there are two possible values of N.

8 0
3 years ago
Solve the equation 1/6(x - 5) = 1/2(x + 6)
Semmy [17]

Answer:

-23/2

Step-by-step explanation:

x-5=3(x+6)

x-3x=18+5

-2x=23

x=-23/2

5 0
2 years ago
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