<span>If two events are independent, the occurrence of one event does not affect the other.
That is if two events are independent, then P(Aâ©B)=P(A)P(B)
Let A be the even getting a sum of 6 in a single roll of two dice.
Sample space of A ={(1,5)(5,1)(2,4)(4,2)(3,3)}
n(A)=5; n(S)=36
Therefore P(A) =n(A)/n(S) =5/36 ---------(1)
Let B be the event of rolling doubles.
Sample space for B ={(1,1)(2,2)(3,3)(4,4)(5,5)(6,6)}
n(B)=6;n(S)=36
P(B) = n(B)/n(S) = 6/36 --------------(2)
Aâ©B is the event of getting a sum of 6 and rolling doubles.
Therefore n(Aâ©B)=1
P(Aâ©B)=1/36 ------(3)
Multiplying equation (1) and (2)
(5/36)*(6/36)=5/216
but P(Aâ©B)=1/36
P(Aâ©B) ≠P(A)P(B)
Therefore, the events are not independent.</span>
Answer:
i do not no sorry
Step-by-step explanation:
:( i will try and figure it out my friend.
The answer is 0,1,4,34,123
Amount raised from selling candy bars = $ 1036.25.
Amount raised from dance ticket sales = $524 and
Amount raised from valentines flower sales = $206.58.
In order to find the amount your class raise altogether, we need to add all those amounts.
Total amount = $ 1036.25 + $524 + $206.58 = $1766.83.
Therefore, your class raise $1766.83 altogether.
