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2 years ago

Simplify -6 . 2 041 318 4 8 318

Mathematics

1 answer:

PilotLPTM [1.2K]2 years ago

8 0

$- 6 \frac{1}{4} - ( - 2 \frac{1}{8} )$

$= - 6 \frac{1}{4} + 2 \frac{1}{8}$

$= \frac{ - 25}{4} + \frac{17}{8}$

$= \frac{ - 50}{8} + \frac{17}{8}$

$= \frac{ - 50 + 17}{8}$

$= \frac{ - 33}{8}$

$= - 4 \frac{1}{8}$

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Is the number 3 a rational number?

VikaD [51]

Answer:

Yes.

Step-by-step explanation:

The number 3 is a natural number, and all of these types of numbers are rational.

Another way to look at it is if a number can be written as a fraction, the number is rational.

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3 years ago

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A new operation is defined by a△b=a^2-b/b-a^2. 4△3.

dmitriy555 [2]

As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1

As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.

Given, a△b=a^2-b/b-a^2

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4△3 = 13 / -13

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1 year ago

Which graph shows the solution to the following inequality? 4d-6<18

Nadusha1986 [10]

Answer: C

Step-by-step explanation:

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3 years ago

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Three rays have a common vertex on a line. Write and solve equations to find the measures of m and n

lukranit [14]

Answer:

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3 years ago

To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil

Debora [2.8K]

Answer:

statistic value t= 5.43

p-value: < 0.00001.

Step-by-step explanation:

Hello!

To obtain information over the corrosion-resistance properties of a certain type of steel conduit a random sample of 45 specimens was taken and buried for two years.

The study variable is:

X: Max. penetration of a steel conduit.

The data of the sample

n= 45

sample mean X[bar]= 53.4

sample standard deviation S= 4.2

The conduits are manufactured to have a true average penetration of at most 50 mills, symbolically: μ ≤ 50

The hypothesis is:

H₀: μ ≤ 50

H₁: μ > 50

α: 0.05

To choose the corresponding statistic to use to study the population mean, the variable must have a normal distribution. There is no available information to check this, so I'll just assume that the variable has a normal distribution and, since the population variance is unknown and the sample is small, the statistic to use is a Student t.

Under the null hypothesis, the critical region and the p-value are one-tailed.

Critical value:

$t_{n-1; 1-\alpha } = t_{44; 0.95} = 1.68$

Rejection rule:

Reject the null hypothesis when t ≥ 1.68

t= $\frac{53.4 - 50}{\frac{4.2}{\sqrt{45} } }$

t= 5.43

The calculated value is greater than the critical value, thedecision is to rject the null hypothesis.

p-value:

P(t ≥ 5.43) = 1 - P(t < 5.43) = < 0.00001.

The p-value is less than α so the decision is to reject the null hypothesis.

Since the null hypothesis was rejected, then the population average of the penetration of the conduits specimens is greater than 50 mils. It is not recommendable to use these conduits.

I hope it helps!

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3 years ago