All categories

3 years ago

Does anyone know this?? Pls help!

Mathematics

2 answers:

kozerog [31]3 years ago

8 0

Answer: x^3 -12x^2+31x-96+ 292/x+3

The remainder is 292

Step-by-step explanation: I used synthetic division to get the answer and got the answer above. I hope this helped :)

Paraphin [41]3 years ago

6 0

P(-3) = 3^4-9*3^3-5*3^2-3*3+4
=81 - 189 -45 -9 +4
= -158
I think

You might be interested in

The equation 4x-45=y is used to find your profit y in dollars from buying $45 of supplies and washing cars for $4 what does the

Mrrafil [7]

33333333333333336666666666

5 0

3 years ago

Help please will mark brainliest!!!

Daniel [21]

Answer:

45°

Step-by-step explanation:

Well, compared to 90°, it looks like it's just smaller, but not too small. It couldn't be 15° degrees, or 60°, as it was probably too much. I Don't think it's 30° either, because it looked bigger than what a 30° angle would be.

Hope it helped!

~Flip

7 0

3 years ago

2 At Bea's Pet Shop, the number of dogs, d, is initially five less than twice the number of cats, c. If she decides to add three

forsale [732]

Let D be dogs and C be cats

dogs, d, is initially five less than twice the number of cats, c

D + 5 = 2C

If she decides to add three more of each, the ratio of cats to dogs will be

D + 8 = 2C + 3

Could Bea's Pet Shop initially have 15 cats and 20 dogs?

Simply plug in the numbers

20 + 5 = 2(15)

This is clearly not true: 25 does not equal 30

7 0

3 years ago

Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas

lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

$n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)$

$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

$n(S \cap F) = 24$

So the correct answer is:

b) 24

3 0

3 years ago

PLEASE ANSWER I WILL MARK AS BRAINLIEST

Tomtit [17]

Answer:

Six

Step-by-step explanation:

1.Convert all volumes to millilitres

(a) Chlorpheniramine

V = 100 mL

(b) Lidocaine

$V = \text{2 fl oz} \times \dfrac{\text{29.57 mL}}{\text{1 fl oz}} = \textbf{59 mL}$

(c) Banana flavouring

$V = \dfrac{1}{2}\text{ tsp} \times \dfrac{\text{4.928 mL}}{\text{1 tsp}} = \textbf{2.5 mL }$

2. Calculate the total volume

Chlorpheniramine = 100 mL

Lidocaine = 59

Banana flavouring = 2.5

TOTAL = 162 mL

3. Calculate the number of doses

$\text{Doses} = \text{162 mL} \times \dfrac{\text{1 dose}}{\text{10 mL}} = \text{16.2 doses}\\\\\text{You can't take a fraction of a dose, so the there are $\large \boxed{\textbf{16 doses}}$}$

5 0

3 years ago