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mr_godi [17]
3 years ago
13

Does anyone know this?? Pls help!

Mathematics
2 answers:
kozerog [31]3 years ago
8 0

Answer: x^3 -12x^2+31x-96+ 292/x+3

The remainder is 292

Step-by-step explanation: I used synthetic division to get the answer and got the answer above. I hope this helped :)

Paraphin [41]3 years ago
6 0
P(-3) = 3^4-9*3^3-5*3^2-3*3+4
=81 - 189 -45 -9 +4
= -158
I think


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The equation 4x-45=y is used to find your profit y in dollars from buying $45 of supplies and washing cars for $4 what does the
Mrrafil [7]
33333333333333336666666666
5 0
3 years ago
Help please will mark brainliest!!!
Daniel [21]

Answer:

45°

Step-by-step explanation:

Well, compared to 90°, it looks like it's just smaller, but not too small. It couldn't be 15° degrees, or 60°, as it was probably too much. I Don't think it's 30° either,  because it looked bigger than what a 30° angle would be.

Hope it helped!

~Flip

7 0
3 years ago
2 At Bea's Pet Shop, the number of dogs, d, is initially five less than twice the number of cats, c. If she decides to add three
forsale [732]

Let D be dogs and C be cats

<em>dogs, d, is initially five less than twice the number of cats, c</em>

D + 5 = 2C

<em>If she decides to add three more of each, the ratio  of cats to dogs will be</em>

D + 8 = 2C + 3

<em>Could Bea's Pet Shop initially have 15 cats and 20 dogs?</em>

Simply plug in the numbers

20 + 5 = 2(15)

This is clearly not true: 25 does not equal 30

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7 0
3 years ago
Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas
lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

n(S) = n(s) + n(S \cap F)

In which n(s) are those who are succeful but not freshmen and n(S \cap F) are those who are succesful and freshmen.

By the same logic, we also have that:

n(F) = n(f) + n(S \cap F)

The union is:

n(S \cup F) = n(s) + n(f) + n(S \cap F)

In which

n(S \cup F) = 58

n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)

n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)

So

n(S \cup F) = n(s) + n(f) + n(S \cap F)

58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)

n(S \cap F) = 24

So the correct answer is:

b) 24

3 0
3 years ago
PLEASE ANSWER I WILL MARK AS BRAINLIEST
Tomtit [17]

Answer:

Six

Step-by-step explanation:

1.Convert all volumes to millilitres

(a) Chlorpheniramine

V = 100 mL

(b) Lidocaine

V = \text{2 fl oz} \times \dfrac{\text{29.57 mL}}{\text{1 fl oz}} = \textbf{59 mL}

(c) Banana flavouring

V = \dfrac{1}{2}\text{ tsp} \times \dfrac{\text{4.928 mL}}{\text{1 tsp}} = \textbf{2.5 mL }

2. Calculate the total volume

Chlorpheniramine = 100  mL

Lidocaine               =   59

Banana flavouring =  <u>   2.5    </u>

TOTAL                    =  162 mL

3. Calculate the number of doses

\text{Doses} = \text{162 mL} \times \dfrac{\text{1 dose}}{\text{10 mL}} = \text{16.2 doses}\\\\\text{You can't take a fraction of a dose, so the there are $\large \boxed{\textbf{16 doses}}$}

5 0
3 years ago
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