The discriminant of a polynomial is given by:
b ^ 2-4ac
Substituting the values we have:
(-24) ^ 2-4 * (3) * (12) = 432
Since the discriminator is greater than zero, then the roots are real.
x = (- b +/- root (b ^ 2-4ac)) / (2a)
Substituting the values:
x = (- (- 24) +/- root (432) / (2 * (3))
x = (- (- 24) +/- root (432) / (2 * (3))
x = (- (- 24) +/- root (144 * 3) / (2 * (3))
x = (24 +/- 12raiz (3) / (6)
x = 4 +/- 2raiz (3)
The roots are:
x1 = 4 + 2raiz (3)
x2 = 4 - 2raiz (3)
Answer:
432
the roots are real.
x1 = 4 + 2raiz (3)
x2 = 4 - 2raiz (3)
Answer:
SAS theorem
Step-by-step explanation:
Given



Required
Which theorem shows △ABE ≅ △CDE.
From the question, we understand that:
AC and BD intersects at E.
This implies that:

and

So, the congruent sides and angles of △ABE and △CDE are:
---- S
---- A
or
--- S
<em>Hence, the theorem that compares both triangles is the SAS theorem</em>
Answer: $28.30✔️
Step-by-step explanation:
Let C = cost before tax
Cell phone costs = C + C·6% = $30
C(1 + 0.06) = $30
C = $30/1.06 = $28.30
Answer: $28.30✔️
<h3> Verify </h3>
Cell phone after tax = $28.30 + $28.30·6/100 = $28.30 + $1.70 = $30✔️
<h2><em>Spymore </em></h2>