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Greeley [361]
3 years ago
10

Solve each equation. I don't know this

Mathematics
1 answer:
MArishka [77]3 years ago
5 0
1.(2x - 3)(x + 7) = 0
   2x^{2} + 14x - 3x - 21 = 0                                  
   2x^{2} + 11x - 21 = 0                       
  
   x = \frac{-11 +/- \sqrt{11^{2} - 4(2)(-21)}}{2(2)}                 
  
   x = \frac{-11 +/- \sqrt{121 + 168}}{4}
  
   x = \frac{-11 +/- \sqrt{289}}{4}
  
   x = \frac{-11 +/- 17}{4}
  
   x = -2.75 +/- 4.25
   x = -2.75 + 4.25                     x = -2.75 - 4.25
   x = 1.5                                                   <u></u>x = -7
----------------------------------------------------------------------------------------------------------  2.8x(2x - 5) = 0
   8x(2x) - 8x(5) = 0
   16x^{2} - 40x = 0
   16x^{2} - 4x + 0 = 0
  
   x = \frac{-(-40) +/- \sqrt{(-40)^{2} - 4(16)(0)}}{2(16)}
  
   x = \frac{40 +/- \sqrt{1600 - 0}}{32}
  
   x = \frac{40 +/- \sqrt{1600}}{32}
  
   x = \frac{40 +/- 40}{32}
  
   x = 1.25 +/- 1.25
   x = 1.25 + 1.25                                  x = 1.25 - 1.25
   x = 2.5                                               x = 0
----------------------------------------------------------------------------------------------------------
3.x^{2} + 3x - 10 = 0
  
   x = \frac{-3 +/- \sqrt{3^{2} - 4(1)(-10)}}{2(1)}
  
   x = \frac{-3 +/- \sqrt{9 + 40}}{2}
  
   x = \frac{-3 +/- \sqrt{49}}{2}
  
   x = \frac{-3 +/- {7}}{2}
  
   x = -1.5 +/- 3.5
   x = -1.5 + 3.5               x = -1.5 - 3.5
   x = 2                             x = -5
----------------------------------------------------------------------------------------------------------
4. x^{2} = 13x - 36
    x^{2} - 13x + 36 = 13x - 13x - 36 + 36
    x^{2} - 13x + 36 = 0
   
    x = \frac{-(-13) +/- \sqrt{(-13)^{2} - 4(1)(36)}}{2(1)}

   
    x = \frac{13 +/- \sqrt{169 - 144}}{2}
  
    x = \frac{13 +/- \sqrt{25}}{2}
 
    x = \frac{13 +/- 5}{2}

    x = 6.5 +/- 2.5
    x = 6.5 + 2.5                     x = 6.5 - 2.5
    x = 9                                 x = 4
----------------------------------------------------------------------------------------------------------
5.3x^{2} - 7x + 2 = 0
  
   x = \frac{-(-7) +/- \sqrt{(-7)^{2} - 4(1)(2)}}{2(3)}

   x = \frac{7 +/- \sqrt{49 - 8}}{6}

   x = \frac{7 +/- \sqrt{41}}{6}

   x = \frac{7 +/- 6.403124237432849}{6}
 
   x = 1.167+/- 1.06718737290547
   x = 1.67 + 1.06718737290547              x = 1.167 - 1.06718737290547
   x = 2.73718737290547                         x = 0.60281262709453
----------------------------------------------------------------------------------------------------------
6.10x^{2} - 10x + 9 = 5x^{2} + 4x + 1
   10x^{2} - 5x^{2} - 10x + 10x + 9 - 1 = 5x^{2} - 5x^{2} + 4x + 10x + 1 - 1
   5x^{2} + 8 = 14x
   5x^{2} - 14x + 8 = 14x - 14x
   <u />5x^{2} - 14x + 8 = 0
  
   x = \frac{-(-14) + \sqrt{(-14)^{2} - 4(5)(8)}}{2(5)}
  
   x = \frac{14 +/- \sqrt{196 - 160}}{10}
  
   x = \frac{14 +/- \sqrt{36}}{10}.
  
   x = \frac{14 +/- 6}{10}
  
   x = 1.4 +/- 0.6
   x = 1.4 + 0.6                x = 1.4 - 0.6
   <u />x = 2                            x = 0.8
 
 
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bekas [8.4K]

Answer:

100% probability that the sample mean weight of these 100 bags is less than 18.6 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 18.5, \sigma = 0.2, n = 100, s = \frac{0.2}{\sqrt{100}} = 0.02

What is the probability that the sample mean weight of these 100 bags is less than 18.6 ounces

This is the pvalue of Z when X = 18.6. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{18.6 - 18.5}{0.02}

Z = 5 has a pvalue of 1

100% probability that the sample mean weight of these 100 bags is less than 18.6 ounces

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Step-by-step explanation:

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The percent of the increase is

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I is the increasing value

N is the new value

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The price of the cooler is $28.50, then

O = 28.50

The selling price of the cooler is $40.76, then

N = 40.76

We will substitute them in the rule above to find I

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Answer:

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Step-by-step explanation:

First find the slope of the given line by converting to intercept form:

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y = -3x - 2

So the slope is -3.

Then the line we want has a slope of -3 also (as it is parallel).

y - y1 = m(x - x1)   where m is the slope and (x1, y1) is a point on the line:

m = -3,  x1 = 1 and y1 = 4, so we have:

y - 4 = -3(x - 1)

y = -3x + 3 + 4

y = -3x + 7.

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