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zavuch27 [327]
3 years ago
12

F(x)=20-x^2+8x what are the minimum and maximum points and the axis of symmetry?

Mathematics
1 answer:
-Dominant- [34]3 years ago
5 0
Vertex aka max or min point is found by -b/2a in form
f(x)=ax^2+bx+c
f(x)=-1x^2+8x+20
vertex x value is -8/(2)(-1)=-8/-2=4
input back to find y value
f(4)=-(4^2)+8*4+20
f(4)=-16+32+20
f(4)=36
max (since the graph opens down) is (4,36)
axis of symmetry is the x coordinate


max is (4,36)
axis of symmetrry is x=4
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