HELP PLEASEEEEEEE!!!!

Mathematics

2 answers:

Neko [114]3 years ago

8 0

Step-by-step explanation:

answer/ explanation is in the picture

timofeeve [1]3 years ago

8 0

Answer:

2.02units

Step-by-step explanation:

tan68°= $\frac{5}{x}$ =2.4750868534163,so x ≈2

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Hailey, Carla and Britney had a contest

Julli [10]

Answer:

Hailey won by holding her breath for 102 seconds

Step-by-step explanation:

Britney held her breath for 44 seconds

Carla held her breath for 88 seconds

Hailey held her breath for 102 seconds

6 0

3 years ago

Read 2 more answers

Answer for these 2 plz? With explanation!

givi [52]

Answer:

Look at the photo

Step-by-step explanation:

I hope I solved it right. Once you get the main concept of it, it's pretty easy.

If you have any questions about the way I solved it, don't hesitate to ask

8 0

3 years ago

If a sample of 14 students were taken from a population of 168 students, o?

garri49 [273]

14 is correct (B). Hope it helps

6 0

3 years ago

if I have a 71 percent in a class and I take a final worth 10 percent of my grade and fail. what would my grade be? thanks in ad

maria [59]

I think you're asking for a numerical answer, but you didn't mention
your score on the final.

Since the final is worth 10% (one tenth) of the grade, that 71 that you
have going into the final is worth 9/10 of the grade. So the way you
calculate your overall average is

 Overall score = 1/10 of [ (71 x 9) + score on the final ] .

If you scored absolute zero on the final, your overall average would be

Overall score = (1/10) x [ (71 x 9) + 0 ] = (1/10) (639) = 63.9% .

That's the lowest overall score for the class that you can have.

The highest overall score you could have would be if you got 100% on the final.
Then
 Overall = (1/10) x (639 + 100) = (1/10) x (739) = 73.9% .

If you got a 50% on the final, your overall would be

 (1/10) x (639 + 50) = (1/10) x (689) = 68.9% .

In general, your overall score for the class, after the final, is going to be

 63.9% plus (1 tenth) of your score on the final.

Good luck !

7 0

4 years ago

Read 2 more answers

In a journey of 15 miles, two third distance was travelled with 40 mph and remaining with 60 mph. How much time does the journey

Ad libitum [116K]

The first step in solving this question is to split the journey into 2 parts. In the first part of the journey, $\frac{2}{3} \times 15 = 10$ miles are covered at a speed of 40 mph. In the second part the journey 5 miles are covered at a speed of 60 mph.

The equation to compute the time of a journey given the speed and distance is $t=\frac{d}{s}$ where $t$ is the time, $s$ is the speed and $d$ is the distance.