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miv72 [106K]
3 years ago
9

at a certain time of day, a tree that is X meters tall casts a shadow that is x-34 meters long. if the distance from the top of

the tree to the end of the shadow is x+2 meters long. what is the height x of the tree?? PLEASE HELP!
Mathematics
1 answer:
stiv31 [10]3 years ago
8 0

Try reviewing your lesson and use symbolab.com a lot of tools on that website that could help you out with this problem

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Arithmetic average of real nonnegative numbers is always smaller than or equal to geometric average. Group of answer choices Tru
noname [10]

Answer:

False

Step-by-step explanation:

Actually, the arithmetic average (or mean) is always greater or equal than the geometric average. This is known as the Arithmetic-Geometric inequality (AM inequality). Let a,b be two real numbers, then the AM inequality states that

\frac{a+b}{2}\geq \sqrt{ab}

To see that the given statement is false, consider a=1, b=3. The arithmetic mean is equal to (1+3)/2=2, and the geometric mean is equal to \sqrt{1\cdot 3}=\sqrt{3} but 2>\sqrt{3}, contrary to the statement (arithmetic>geometric in this case).

4 0
3 years ago
Please help!
SpyIntel [72]
Number 1 is B
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3 0
3 years ago
Find the product and quotient please!!!! <br> 0.48 times -1.72times 0
PolarNik [594]

Harvey keep him he needed can u I

4 0
3 years ago
What sum will amount to rupees 4000 in 3 years at 6% p.a. compound interest​
natali 33 [55]

Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Given:}}}}}}}\end{gathered}

  • ⇢ Principle = Rs.4000
  • ⇢ Rate = 6%
  • ⇢ Time = 3 year

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{To Find:}}}}}}}\end{gathered}

  • ⇢ Amount

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Using Formula:}}}}}}}\end{gathered}

{\dag{\underline{\boxed{\sf{Amount  ={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}

\dag{\underline{\boxed{\sf{Compound \: Interest = Amount- Principle }}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Solution:}}}}}}}\end{gathered}

{\bigstar \:{\underline{\pmb{\frak{\red{Firstly,Finding  \: the  \: Amount }}}}}}

\quad {:\implies{\sf{Amount  = \bf{P{\bigg(1  +  \dfrac{R}{100}{\bigg)}^{T}}}}}}

  • Substituting the values

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg(1  +  \dfrac{6}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg(1 \times 100  +  \dfrac{6}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{100 + 6}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{106}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg({\cancel{\dfrac{106}{100}}{\bigg)}}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{53}{50}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{53}{50} \times \dfrac{53}{50} \times \dfrac{53}{50}{\bigg)}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{148877}{125000}{\bigg)}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000 \times  \dfrac{148877}{125000}}}}}

\quad {:\implies{\sf{Amount  = \bf{4{\cancel{000}} \times  \dfrac{148877}{125{\cancel{000}}}}}}}

\quad {:\implies{\sf{Amount  = \bf{\dfrac{148877 \times 4}{125}}}}}

\quad {:\implies{\sf{Amount  = \bf{\dfrac{595508}{125}}}}}

\quad {:\implies{\sf{Amount  = \bf{\cancel{\dfrac{595508}{125}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4764.064}}}}

\begin{gathered} \dag{\boxed{\textsf{\textbf{\underline{\color{green}{Amount = {Rs.4764.064}}}}}}}\end{gathered}

  • Hence, The Amount is Rs.4764.064

\begin{gathered}\end{gathered}

{\bigstar \:{\underline{\pmb{\frak{\red{ Now,Finding  \: The \:  Compound \:  Interest }}}}}}

\quad{: \implies{\sf{Compound \: Interest =  \bf{Amount- Principle }}}}

  • Substituting the values

\quad{: \implies{\sf{Compound \: Interest = \bf{4764.064- 4000 }}}}

\quad{: \implies{\sf{Compound \: Interest =\bf{764.064}}}}

\begin{gathered} \dag{\boxed{\textsf{\textbf{\underline{\color{green}{Compound Interest  = Rs.764.064}}}}}}\end{gathered}

  • Henceforth,The Compound Interest is Rs.764064

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Learn More:}}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}

8 0
3 years ago
Find x,y, and z and please show all work.
lana [24]

Answer:

x = 47°

y = 10

z = 5

Step-by-step explanation:

They share the middle line which is one side. It's given that side y is congruent to the side with a value of 5. Angle X and the non labeled angel are also congruent to each other. Using SAS (side angle side) we can conclude the 2 triangles are congruent, which means all angles and sides are congruent and equal.

The angles of a triangle add to 180.

x+90+43=180

x=47

z is congruent/equal to 5 since they are congruent and equal triangles. Therefore z=5

Y is congruent to side 10, which also means it is equal to 10. Therefore y=10

6 0
3 years ago
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