For a trapezoid, the area is:
S=(b+B)h/2, where b and B are the bases, and h is the height.
b=2
B=2+2+2=6
h=2.
S=(2+6)×2/2=8
Answer: 61.92751306414704
Step-by-step explanation:
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750
Correct answer is C)</span>
Answer:
Step-by-step explanation:
1. 10² + 7² = x²
149 = x²
x = √149
2. x² + 19² = 21²
x² = 21² - 19² = 80
x = √80 = 4√5
3. x² + 16² = 27²
x² = 27² - 16² = 473
x = √473
4. 5.3² + 12.8² = x²
191.93 = x²
x = √191.93
5. 9² + 20² = x²
481 = x²
x = √481
6. 31 = x + 2√(19²-17²) = x + 2·6√2 = x + 12√2
x = 31 - 12√2
