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3 years ago

How do I find the domain of f(x)=5x^2+4. When 0<=x<=2 #54

Mathematics

1 answer:

Blizzard [7]3 years ago

4 0

if 0 ≤ x ≤ 2

$0^2\leq x^2\leq 2^2$

Multiplied by 5..... $5×0^2 \leq 5x^2\leq 5×2^2$

add 4 ......... $5×0^2+4 \leq 5x^2+4\leq 5×2^2$ +4

so ........ $4\leq 5x^2+4\leq 24$

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