Answer:
if it's finding x
#1 x<-1
#2 x<4
Step-by-step explanation:
#1
2x-16<-18
add 16 to both sides
2x<-2
then divide 2 to both sides
x<-1
#2
2x-16+4x<8
add like terms
6x-16+<8
add sixteen to both sides
6x<24
divide six to both sides
x<4
Answer:
in 4/5 fraction of the game they scored two or more runs.
Answer:
ang hirap wag nlang hahahahahahahaha
22.5/(x-6) + 22.5/(x+6) = 9
multiply by x-6
=> (x-6)22.5/(x-6) + (x-6)22.5/(x+6) = 9(x-6)
=> 22.5 + (x-6)22.5/(x+6) = 9(x-6)
multiply by x+6
=> (x+6)22.5 + (x+6)(x-6)22.5/(x+6) = 9(x-6)(x+6)
=> (x+6)22.5 + (x-6)22.5 = 9(x-6)(x+6)
distribute
=> 22.5x+6(22.5) + 22.5x - 6(22.5) = 9(x^2 - 36)
=> 45x = 9x^2 - 9(36)
=> 0 = 9x^2 - 45x - 9(36)
divide by 9
=> 0 = x^2 - 5x - 36
=> 0 = x^2 - 5x - 36
=> 0 = (x - 9)(x + 4)
x=9 and -4
I am assuming 33 is B^(2/3) times B^(1/2)
See the following image
