Explain how you decide whether the final answer to a multiplication problem is

Mathematics

1 answer:

Evgesh-ka [11]3 years ago

8 0

Explanation:

Regardless of the number of factors, the product will be negative if an odd number of factors are negative.

In the example, 3 of the factors are negative. 3 is an odd number so the product will be negative.

-2*-3*-1*1 = -6

_____

Of course, the product will be zero if any factor is zero, regardless of the signs of any other factors.

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Eliminate the parameter,t, in the parametric equation, x=6cos t, and y =3 sin t

german

X = 6 cos(t)
y = 3 sin(t)

we can rewrite these equations as:

$\frac{x}{6}=cost(t) \\ \\ \frac{y}{3} =sin(t)$

Taking squares of both equations we get:

$( \frac{x}{6})^{2}=sin^{2} (t) \\ \\ 
( \frac{y}{3})^{2}=cos^{2}(t)$

Adding both the equations, we get:

$\frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=sin^{2}(t)+cos^{2}(t) \\ \\ 
 \frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=1$

6 0

3 years ago

Perform the indicated operation and simplify the result. Leave your answer in factored form.

Aliun [14]

Answer:

$\frac{x }{x^{2}-9 } +\frac{9}{x}=\frac{x^{2} }{x(x^{2}-9) }+\frac{9(x^{2}-9) }{x(x^{2} -9)}\\\\=\frac{10x^{2} -81}{x(x-3)(x+3)}$