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3 years ago

Solve and check times six equals 12 / 9

1 answer:

4 0

Okay so your gonna go across diagonally and multiply because it is a proportion problem so it turns out looking like this:
x(9) = 12(6)

8x =72

x = 9

Now just put it in:
9/6 = 12/9
And see that it correlates!

I hope that helps! :)

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Name the property being used 2+(3+7)=(2+3)+7

aleksklad [387]

Answer: Associative property

Explanation: The associative property is a math rule that says that the way in which factors are grouped in a multiplication problem does not change the product. Example: 5 × 4 × 2 5 \times 4 \times 2 5×4×2.

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3 years ago

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FOR BRAINLSIT!!! A B C D

Phantasy [73]

Answer:

The 2nd option is correct

Step-by-step explanation:

The only numbers on a dice greater than 4 are 5 and 6, and we want to get the color blue, so the 2nd option is correct.

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3 years ago

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100POINTS!!!! PLEASE HELP EXPLAIN YOUR ANSWER!!! BRAINLIEST!!!

Nitella [24]

Example: Does the point (5, 2) lie within the solution set of the given system of inequalities?

y ≤ x − 5

y ≥ −x − 4

Focus on the first inequality. Does (5,2) satisfy this inequality? Is 2 ≤ 5 - 0 true? Yes, it is true. Before we call (5,2) a solution, we must determine whether or not (5,2) also satisfies the 2nd inequality: Is 2 ≥ -(5) - 4 true?

Is 2 ≥ -9? Yes! So, yes, (5,2) is a solution of this system of inequalities.

We must check out the other three possible solutions in the same fashion.

Try out the point (5,-2). Does it satisfy both inequalities?

Focusing on the first inequality: Is -2 ≤ 5 - 5 true? Yes, it is. The key question here and now is whether or not (5,-2) also satisfies y ≥ −x − 4. Is

-2 ≥ -(5) - 4 true? Is -2 ≥ -9 true? Yes. Thus, (5,-2) satisfies both inequalities and is thus another solution.

Check out (-5,2) and (-5,-2) in precisely the same way. Is either one, or are both, a solution (or solutions) to the given set of inequalities?

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3 years ago

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Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3

Serhud [2]

Answer:

$e^{3t}(2t+5t^{2})$

Step-by-step explanation:

$L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=$

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem: $L^{1} [F(s-a)=L^{-1}[F(s)|_{s \to s-a}\\ L^{1} [F(s-a)=e^{at} f(t)$

$L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=e^{3t} L^{-1}[\frac{2(s+3)+4}{s^{3}} ]$

Separate the fraction in a sum:

$e^{3t} L^{-1}[\frac{2s+10}{s^{3}} ]=e^{3t} L^{-1}[\frac{2s}{s^{3}}+\frac{10}{s^{3}} ]=e^{3t} (L^{-1}[\frac{2}{s^{2}}]+ L^{-1}[\frac{10}{s^{3}}])$

The formula for this is:

$L^{-1}[\frac{n!}{s^{n+1}} ]=t^{n}$

Modify the expression to match the formula.

$e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ \frac{10}{2} L^{-1}[\frac{2}{s^{2+1}}])=e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])$

Solve

$e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])=e^{3t}(2t+5t^{2} )$

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3 years ago

Will give brainliest! and EXTRA points.

denis23 [38]

How far did the frog jump? the answer is one of the solutions of the quadratic equation

$0= -0.017x^2+0.51x$

because that's where the frogs height is 0 (y=0) feet.

Use your favorite formula for quadratic equations. I got two solutions: 0 and 30. 0 is clearly the starting point and 30 feet is point where the frog lands.

The height is the maximum of the quadratic form. Use the formula for maximum x of a quadratic: xmax = -b/(2a) = -0.51/(2*0.017) = 15. The maximum at that point is ymax = 3.825

So, the correct answer is (a) 30 ft far and 3.83 high.

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4 years ago