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3 years ago

Please help! Correct answer gets brainlist+all answers get thanks!

Mathematics

2 answers:

galina1969 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

x^-3 times ^-2= x^6

y^3 times ^-2= y^-6, the negative causes it to become the denominator.

4 to the power of -2 = 16, causing it to move to the numerator, since it is positive.

16x^6/y^6

Tresset [83]3 years ago

4 0

Answer:

B) 16x⁶/y⁶

Step-by-step explanation:

(x^-3 × y^3 ÷ 4)^-2

x^(-3×-2) × y^(3×-2) ÷ 4^(-2)

x⁶ × 1/y⁶ × 4²

16x⁶/y⁶

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!!!WILL MARK THE BRAINIEST!!!

Nina [5.8K]

Answer:

$1/65536$

Step-by-step explanation:

$4^-8 \times 4^0$

$1/4^8 \times 1$

$1/4^8$

$=0.00001525878$

5 0

3 years ago

Read 2 more answers

What is this equation, equivalent to c(x)=(x+6)^2+14

Digiron [165]

<h3>Answer: x^2+12x+50</h3>

Work Shown:

c(x) = (x+6)^2+14

c(x) = (x+6)(x+6)+14

c(x) = x(x+6)+6(x+6)+14

c(x) = x^2+6x+6x+36+14

c(x) = x^2+12x+50

7 0

3 years ago

Find the differential of each function. (a) y = tan( 7t ) dy = Incorrect: Your answer is incorrect. (b) y = 4 − v2 4 + v2 dy =

Kisachek [45]

Answer:

$(a) dy= 7sec^2(7t)dt\\\\(b) dy = \frac{-16v}{(4+v^2)^2} dv$

Step-by-step explanation:

Given;

(a) y = tan (7t)

let u = 7t

y = tan(u)

du/dt = 7

dy/du = sec²(u)

$\frac{dy}{dt} = \frac{dy}{du} *\frac{du}{dt}\\\\\frac{dy}{dt} = sec^2(u)* 7\\\\\frac{dy}{dt} =7sec^2(u)\\\\\frac{dy}{dt} = 7sec^2(7t)\\\\dy = 7sec^2(7t)dt$

(b)

$y = \frac{4-v^2}{4+v^2}\\\\$

let u = 4 - v²

du/dv = -2v

let v = 4 + v²

dv/du = 2v

$y = \frac{4-v^2}{4+v^2}\\\\\frac{dy}{dv} = \frac{vdu-udv}{v^2} \\\\\frac{dy}{dv} =\frac{-2v(4+v^2)-2v(4-v^2)}{(4+v^2)^2}\\\\\frac{dy}{dv} =\frac{-8v-2v^3-8v+2v^3}{(4+v^2)^2}\\\\\frac{dy}{dv} =\frac{-16v}{(4+v^2)^2}\\\\dy = \frac{-16v}{(4+v^2)^2}dv$