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Reptile [31]
3 years ago
7

The president of a college has been told that when they raised their tuition by 15 percent the previous year, total revenue from

tuition remained unchanged. Assuming the change in revenue is due to the change in tuition only, the president could conclude that demand for that college, over that tuition range, must be:
Mathematics
2 answers:
rodikova [14]3 years ago
7 0

Answer:

demand for the college is equal to 1

Step-by-step explanation:

- We know that the change in Total Revenue is only the function of change in tuition fee only.

- The change in tution fee is subjected to 15% last year multiplied by the corresponding change in demand for the college will lead to a change in total revenue.

- The relation can be expressed as:

                                         ΔTR =  Δ P *ΔD

Where,

         ΔTR : Change in Total Revenue

         Δ P : Change in tuition fee

         ΔD : Change in demand.

- For TR to remain unchanged then ΔTR = 0. Hence,

                                         ΔTR = 0 = Δ P *ΔD

- We are given a change in Δ P = 15%, so that means for ΔTR = 0, the change in demand ΔD = 0.

- ΔD = 0, also means that the elasticity of the demand curve is perfectly elastic or in other words the demand for the college is equal to 1.

nalin [4]3 years ago
6 0

Answer:

= 1

Step-by-step explanation:

The demand for that college will be equal to 1 or it can be said as unit elastic demand over the tuition range. This means that the demand for the college would move proportionately with the tuition range of that college, since the change in revenue is due to the change in tuition only.

Hope this helps.

Good luck and cheers.

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NeTakaya

Answer:

14.2

Step-by-step explanation:

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Delaney bought a new car for $34,742 she was surprised that the dealer then added 1,945.55. what was the sales tax rate for this
Gemiola [76]

Answer:

5.6%

Step-by-step explanation:

$34,742. X 5.6% = $1,945.55

6 0
3 years ago
The population of a local species of flies can be found using an infinite geometric series where a1 = 940 and the common ratio i
alex41 [277]

A. Sigma notation

The formula for finding the nth value of the geometric series is given as:

an = a1 * r^n

Where,

an = nth value of the series

<span>a1 = 1st value in the geometric series = 940</span>

r = common ratio = 1/5

n = nth order

The sigma notation for the sum of this infinite geometric series is therefore,

                     (see attached photo)

B. Sum of the infinite geometric series

The formula for calculating the sum of an infinite geometric series is given as:

<span>S = a1  / (1 – r)</span>

Substituting the given values:

S = 940 / (1 – 1/5)

<span>S = 1,175</span>

6 0
4 years ago
Help needed!!!
Brrunno [24]

Answer:

A

Step-by-step explanation:

using the theorem of Pythagoras

<em>x</em><em> </em><em>=</em><em> </em><em>sqrt</em><em>*</em><em> </em><em>1</em><em>9</em><em>.</em><em>6</em><em> </em><em>^</em><em>2</em><em> </em><em>-</em><em> </em><em>1</em><em>5</em><em>.</em><em>4</em><em>^</em><em>2</em><em>*</em>

<em>x</em><em> </em><em>=</em><em> </em><em>7</em><em>×</em><em> </em><em>sqrt</em><em>*</em><em> </em><em>3</em><em>*</em>

<em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>.</em><em>1</em><em> </em><em>units</em><em> </em>

5 0
3 years ago
Combine like terms to create an equivalent expression -3.6-1.9t+1.2+5.1t
uranmaximum [27]

Answer:

3.2t-2.4

Step-by-step explanation:

The polynomial given for simplification is:

-3.6-1.9t+1.2+5.1t

Now, we combine like terms using the commutative property of addition.

The commutative property of addition states that:

a+b=b+a

So, the order can be shuffled when we add terms.

The terms containing 't' are grouped together and the constant terms are grouped together. This gives,

-1.9t+5.1t+1.2-3.6

Now, we group them using associative property and converse of distributive property as:

(-1.9+5.1)t+(1.2-3.6)

Simplifying the above expression, we get:

(-1.9+5.1)t+(1.2-3.6)\\3.2t-2.4

Therefore, the simplified form is 3.2t-2.4

6 0
4 years ago
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