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pantera1 [17]
4 years ago
9

The sampling distribution of the sample means a. is used as a point estimator of the population mean μ. b. is an unbiased estima

tor. c. shows the distribution of all possible values of μ. d. is the probability distribution showing all possible values of the sample mean.
Mathematics
1 answer:
Firdavs [7]4 years ago
3 0

Answer:

d. is the probability distribution showing all possible values of the sample mean.

Step-by-step explanation:

The sampling distribution of the sample means is normal for large sample sizes and samples randomly drawn irrespective of the original distribution of the random variable.

In other words, the probability distribution showing all possible values of the sample mean is the sampling distribution of sample mean.  Here sample mean is treated as a random variable and its distribution is discussed.

Hence correct option is

d. is the probability distribution showing all possible values of the sample mean.

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Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

\bar {x}_1 = 13.5

\bar {x}_2 = 12

σ₁ = 2.5

σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

8 0
3 years ago
Find the value of 4 5 of ₹90.<br><br><br>answer pls
marshall27 [118]

Answer:

₹ 72

Step-by-step explanation:

= \frac{4}{5} * 90\\\\= \frac{360}{5} \\= 72

8 0
4 years ago
Read 2 more answers
If a 42.9 ft tall flagpole casts a 253.1 ft long shadow then how long is the shadow that a 6.2 ft tall woman casts?
blsea [12.9K]
We will have to use proportions:
\frac{42.9}{253.1}  =  \frac{6.2}{x}
Cross multiplying we get
42.9x = 6.2 \times 253.1
Now divide:
x =  \frac{6.2 \times 253.1}{42.9}
Solve to tenths place we get
x = 36.6
The woman casts a 36.6 ft long shadow.
3 0
4 years ago
The histogram shows the number of morning customers who visited North Cafe and South Cafe over a one-month period. Which predict
vlabodo [156]

The answer to the question is

B. The north restaurant can expect to have 20 fewer morning visitors than the south restaurant.

Hope this helps!

8 0
3 years ago
Read 2 more answers
Sasha hikes into a canyon. She takes a break at the rest stations every 2/3 of a mile. If she started at sea level and has hiked
butalik [34]

the only right one is a, hope this helps

6 0
3 years ago
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