Answer:
4. 3
The answer is the last option, all you do is reduce
Step-by-step explanation:
rise over run = rise/run = 6/2
reduce,
6/2
3/1
3x
<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
Answer:
No It's not
Step-by-step explanation:
Since
x=6 produces y=1 and y=7, the relation (6,1),(8,−3),(6,7) is not a function.
The relation is not a function.
Answer:
First step, add 11 to 44.
Step-by-step explanation:
After that, divide both sides by negative 3.
Answer:
5$
Step-by-step explanation:
32$ -27$ = 5$
as y = 32x and x =1
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