Determine the number of zeros of the polynomial function.f(x) = x3 + 4x2 + 1
1 answer:
Answer:
1 real zero; 2 complex zeros
Step-by-step explanation:
A cubic will have 3 zeros. The number of positive and negative real zeros can be determined using Descartes' rule of signs.
There are no sign changes in the coefficients of the function as written, so there are no positive real roots. (+++)
If odd-degree terms have their sign changed, then there is one sign change. (-++) That indicates there is one negative real root.
The remaining two roots will be complex.
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A graphing calculator can confirm this.
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Delete as this is the wrong answer. Made a typo in the answer.
Answer:
x =
y = 24
Step-by-step explanation:
-3x - 8y = 20 .... (1)
-5x + y = 19 .... (2)
What we can do is take the (2) equation
-5x + y = 19
and solve for y by adding 5x to both sides
y = 24
now that we have y we substitute it in for y in equation (1)
-3x - 8(24) = 20
-3x - 192 = 20
we want to solve for x so we need to get its self.
add 192 to both sides
-3x = 212
now we divide both sides by -3. It's going to be a fraction.
x =