Answer:
![\displaystyle \boxed{|2m| }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%20%5Cboxed%7B%7C2m%7C%20%7D)
Step-by-step explanation:
we are given that
![\displaystyle 2 \sqrt{ {m}^{2} }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%202%20%5Csqrt%7B%20%20%7Bm%7D%5E%7B2%7D%20%7D%20)
since m is greater than or equal to 0 it's a positive number therefore, the square root of m is defined and recall that √x²=|x| thus
![\displaystyle \boxed{2 |m|}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%20%5Cboxed%7B2%20%7Cm%7C%7D)
remember that,|a|•|x|=|ax| hence,
![\displaystyle \boxed{ |2m|}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%20%5Cboxed%7B%20%7C2m%7C%7D)
and we're done!
Answer:
A. Monday
Step-by-step explanation:
The solution to this problem can be found by creating a table
If Day 1 was Monday, then
Mon Tues Wed Thur Fri Sat Sun
1 2 3 4 5 6 7
8 9 10 11 12 13 14
...............
We can see that the multiples of 7 are falling on Sundays so we will divide 36 by 7 to get the closest multiple of 7 to 36.
The closest multiple of 7 near 36 is 35 so Day 35th will fall on Sunday and Day 36 will be on Monday
Hence, Option A is the correct answer..
By setting up a system of equations we can easily solve this problem. Let's denote Jane's working hours with x and Jack's working hours with y. Since they don't want to work more than 65 hours, the first equation is x+y=65. The second equation is 14x+7y=770. By solving this system of equation
![\left \{ {{x+y=65} \atop {14x+7y=770}} \right.](https://tex.z-dn.net/?f=%20%5Cleft%20%5C%7B%20%7B%7Bx%2By%3D65%7D%20%5Catop%20%7B14x%2B7y%3D770%7D%7D%20%5Cright.%20)
, we find that y=20 hours, which is Jack's maximum working hours.