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3 years ago

14

Can someone help me with part B?? I already did part A Thank you so much :)

2 answers:

lara [203]3 years ago

7 0

Answer:

-150

Step-by-step explanation:

this is because you do 250 - 100 which equals -150

kap26 [50]3 years ago

6 0

In part A you subtracted 100 from 100 giving you 0.

Continuing to part B you would subtract 100 from 250 leaving you with 150.

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You are holding a kite string in your hand. The angle of elevation from your hand to the kite is 53∘and the distance to the kite

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Answer:

43 degrees F.

Step-by-step explanation:

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4 years ago

21 marbles out of N are blue; probability of getting a blue one = 30%

MissTica

$Probability=\frac{desired}{total}$
$0.3=\frac{21}{N}$
$0.3N=21$
$N=\frac{21}{0.3}$
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There are 70 total marbles.

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3 years ago

Mr. Nice's backyard has an area of 225 square feet. What is the length of one side of his backyard?

Fittoniya [83]

Answer:

<em>C. 15 feet</em>

Step-by-step explanation:

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3 years ago

Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.2.a. If the distri

zalisa [80]

Answer:

a

$P(\= X \ge 51 ) =0.0062$

b

$P(\= X \ge 51 ) = 0$

Step-by-step explanation:

From the question we are told that

The mean value is $\mu = 50$

The standard deviation is $\sigma = 1.2$

Considering question a

The sample size is n = 9

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{9} }$

=> $\sigma_x = 0.4$

Generally the probability that the sample mean hardness for a random sample of 9 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_{x}} \ge \frac{51 - 50 }{0.4 } )$

$\frac{\= X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ \= X )$

$P(\= X \ge 51 ) = P( Z \ge 2.5 )$

=> $P(\= X \ge 51 ) =1- P( Z < 2.5 )$

From the z table the area under the normal curve to the left corresponding to 2.5 is

$P( Z < 2.5 ) = 0.99379$

=> $P(\= X \ge 51 ) =1-0.99379$

=> $P(\= X \ge 51 ) =0.0062$

Considering question b

The sample size is n = 40

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{40} }$

=> $\sigma_x = 0.1897$

Generally the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_x} \ge \frac{51 - 50 }{0.1897 } )$

=> $P(\= X \ge 51 ) = P(Z \ge 5.2715 )$

=> $P(\= X \ge 51 ) = 1- P(Z < 5.2715 )$

From the z table the area under the normal curve to the left corresponding to 5.2715 and

=> $P(Z < 5.2715 ) = 1$

So

$P(\= X \ge 51 ) = 1- 1$

=> $P(\= X \ge 51 ) = 0$

5 0

3 years ago

Which rigid transformation would map ΔAQR to ΔAKP?

Virty [35]

Rotation around point a

8 0

3 years ago

Read 2 more answers