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3 years ago

Can someone help me with part B?? I already did part A Thank you so much :)

Mathematics

2 answers:

lara [203]3 years ago

7 0

Answer:

-150

Step-by-step explanation:

this is because you do 250 - 100 which equals -150

kap26 [50]3 years ago

6 0

In part A you subtracted 100 from 100 giving you 0.

Continuing to part B you would subtract 100 from 250 leaving you with 150.

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Can u help me pls This homework was due last week I really need help thx xxx

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The ratio of squash to water is 2:7

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2 years ago

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Can there be more than one point of intersection between the graphs of two linear equations

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Yes, Two perpendicular lines

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2 years ago

Fourteen hours after a convict escapes from prison, a guard begins to pursue him. If the convict travels at eight mph on foot an

algol13

9514 1404 393

Answer:

128 miles

Step-by-step explanation:

The convict has a head start of ...

distance = speed × time

distance = (8 mi/h) × (14 h) = 112 mi

That distance is being closed at a rate that is the difference between the speeds, so ...

64 mi/h -8 mi/h = 56 mi/h

The time it takes the guards to catch the convict will be ...

time = distance/speed

time = (112 mi)/(56 mi/h) = 2 h

The guards and prisoner will be at a distance from the prison of ...

distance = speed × time

distance = (64 mi/h)(2 h) = 128 mi

The convict will be caught 128 miles from the prison.

Check

The convict will run an additional (8 mi/h)(2 h) = 16 mi after the guards start pursuit. That, in addition to the 112 miles already run, will total 112+16=128 miles, the same distance the guards travel in that 2 hours.

8 0

3 years ago

PLEASE ANSWER ASAP!!!!!!!

maksim [4K]

A cheesecake has equally sized slices. Each slice is a different flavor. The cheesecake has 12 slices.

<h3>What is the area of the circle?</h3>

The area of the circle is defined as the product of the pie and the square of the radius.

The area of the circle = πr²

In order to calculate the total area of the cheesecake, since it's a circle its area is given by:

cheesecake area = πr²

cheesecake area = π(10/2)² = π(5)²

cheesecake area = 25 π square inches

Therefore the number of slices is the ratio of the cheesecake total area by the area of each slice:

The number of slices = 25 π/(25 π/12)

The number of slices = 12

The cheesecake has 12 slices.

Learn more about circle;

brainly.com/question/12512221

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4 0

1 year ago

. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar

yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total 4+5+6 = 15 bulbs. If we want to select 3 randomly there are K ways of doing this, where K is the combination of 15 elements taken 3 at a time

$K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455$

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

$\frac{270}{455}=0.5934=59.34\%$

(b)

The probability of selecting three 40-W bulbs is

$\frac{4*3*2}{455}=0.0527=5.27\%$

The probability of selecting three 60-W bulbs is

$\frac{5*4*3}{455}=0.1318=13.18\%$

The probability of selecting three 75-W bulbs is

$\frac{6*5*4}{455}=0.2637=26.37\%$

Since the events are disjoint, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

$\frac{6*5*4}{455}=0.2637=26.37\%$

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, supposing there is no replacement, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is $\frac{9}{15}=0.6$

Since there are no replacement, the probability of taking a second non 75-W bulb is now $\frac{8}{14}=0.5714$

Following this procedure 5 times, we find the probabilities

$\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}$

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0

3 years ago