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sasho [114]
3 years ago
7

my 7th-grade math is so har for me plz help me? just the answer or the explianation if u want idc just help!

Mathematics
2 answers:
Allisa [31]3 years ago
4 0

Answer:

The answer is 19/6

Step-by-step explanation:

Vlad1618 [11]3 years ago
3 0
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Please help me figure this out
grin007 [14]
I believe the answer is B
6 0
3 years ago
Read 2 more answers
A support wire is attached to the top of an antenna. The support wire connects
eduard

Answer:

Step-by-step explanation:

4 0
3 years ago
Someone help me please
Mazyrski [523]

Answer:

x = -7

Step-by-step explanation:

The whole line is 12

the whole line is also   x + 14  and  x + 12

  so make them equal:

      x+14     +      x +12     = 12  

       2x   + 26   = 12        now subtract 26 from both sides

               2x = - 14           now divide both sides by 2

                 x = -7

5 0
1 year ago
Read 2 more answers
16
Tanya [424]

Answer:

2.50

Step-by-step explanation:

Given

(x_1,y_1) = (-1,0.8)

(x_2,y_2) = (0,2)

(x_3,y_3) = (1,5)

(x_4,y_4) = (2,12.5)

Required

The rate of change (b)

The above graph is represented as:

y = ab^x

For: (x_2,y_2) = (0,2);

We have:

y = ab^x

2 = a * b^0

2 = a *1

2 = a

a = 2

For (x_3,y_3) = (1,5),

We have:

y = ab^x

5 = a * b^1

5 = a * b

Substitute a = 2

5 = 2 * b

Divide by 2

2.5 = b

b = 2.5

<em>Hence, the rate of change is 2.50</em>

7 0
3 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
2 years ago
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