Answer:
Area = 22.3 m^2
Perimeter 27.4 m^2
Step-by-step explanation:
Perimeter = __ m
Area __ m^2
The area of the triangle is about 4.2,
The area of the square is 4,
The area of the semicircle is 14.1,
14.1 + 4.2 + 4 = 22.3
Area = 22.3 m^2
9.4 + 6 + 4 + 4 + 4 = 27.4
Perimeter = 27.4 m^2
Therefore the area of the shape is about 22.3 m^2 and the perimeter is about 27.4 m^2.
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Menjawab:
y + 2x
Penjelasan langkah demi langkah:
Menulis ulang pertanyaannya
4log5 = x
4log 6 = y
4 log 150 = 4log (2 * 3 * 5 * 5)
= 4log 6 + 4log 5 + 4log 5
Substrat
= y + x + x
= y + 2x
Oleh karena itu ekspresi yang dibutuhkan adalah y + 2x
1/4 ounce of yeast ... 2 1/4 teaspoons of yeast
x ounce of yeast = ? ... 2 teaspoons of yeast
If you would like to know how many ounces of yeast need to be in the recipe, you can calculate this using the following steps:
1/4 * 2 = x * 2 1/4
1/2 = x * 9/4 /*4/9
x = 1/2 * 4/9
x = 2/9
Result: 2/9 ounce of yeast needs to be in this recipe.
Answer:
4 stations
Step-by-step explanation:
If we need to be at least 98% certain that an enemy plane flying over will be detected by at least one station, we must ensure that there is at most a 2% chance that no radar stations detect the plane.
The probability that a single radar station does not detect the plane is 0.35.
For n radar stations:
Rounding up to the next whole station, at least 4 stations are needed.
