Imagine these are your students' test scores (out of 100): 63, 66, 70, 81, 81, 92, 92, 93, 94, 94, 95, 95, 95, 96, 97, 98, 98, 9
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Answer:
The mean ≈ 90
The median = 95
The mode = 95 & 100
The range = 37
Step-by-step explanation:
We will base out conclusion by calculating the measures of central tendency of the distribution i.e the mean, median, mode and range.
– Mean is the average of the numbers. It is the total sum of the numbers divided by the total number of students.
xbar = Sum Xi/N
Xi is the individual student score
SumXi = 63+66+70+81+81+92+92+93+94+94+95+95+95+96+97+98+98+99+100+100+100
SumXi = 1899
N = 21
xbar = 1899/21
xbar = 90.4
xbar ≈ 90
Hence the mean of the distribution is approximately equal to 90.
– Median is number at the middle of the dataset after rearrangement.
We need to locate the (N+1/2)the value of the dataset.
Given N =21
Median = (21+1)/2
Median = 22/2
Median = 11th
Thus means that the median value falls on the 11th number in the dataset.
Median value = 95.
Note that the data set has already been arranged in ascending order so no need of further rearrangement.
– Mode of the data is the value occurring the most in the data. The value with the highest frequency.
According to the data, it can be seen that the value that occur the most are 95 and 100 (They both occur 3times). Hence the modal value of the dataset are 95 and 100
– Range of the dataset will be the difference between the highest value and the lowest value in the dataset.
Highest score = 100
Lowest score = 63
Range = 100-63
Range = 37
Answer:
x = 8
Step-by-step explanation:
Add the four angles given to get 264°
Subtract 264° from the total measure of angles in the pentagram (360°) which gives you 96° for the missing angle measure. From there, it's just basic algebra.
x = 96 ÷ 12
x = 8
9514 1404 393
Answer:
240
Step-by-step explanation:
The generic k-th term of the expansion of the binomial ...
(a +b)^n
is given by ...
(nCk)a^(n-k)b^k . . . . . where nCk = n!/(k!(n-k)!) and 0 ≤ k ≤ n
For this problem, we have ...
a=2x, b=y, n=6, k=2
Then the 2nd term (counting from 0) is ...
6C2×(2x)^4×y^2 = (6·5)/(2·1)·16x^4·y^2
= 240x^4y^2
The desired coefficient is 240.
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<em>Additional comment</em>
The coefficients for the expansion match the numbers in a row of Pascal's triangle. The row beginning with 1, n will have the coefficients for the expansion to the n-th power.
Answer:
1
Step-by-step explanation:
