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Lynna [10]
3 years ago
12

What is the horizontal change between two points on a line

Mathematics
2 answers:
Finger [1]3 years ago
5 0

Answer:

Run

Step-by-step explanation:

Helga [31]3 years ago
4 0
The horizontal change is called the run and the vertical is rise. so for example if one point to the other rises by 4 and runs by 5, the slope is 4/5. slope is
rise / run
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How to graph y = 2|x + 3| - 4
mr_godi [17]

The x-intercepts and the y-intercepts of the function is that determines the graph is:

  • x-intercepts = (-5,0) and (-1,0)
  • y-intercepts = (0,2)

<h3>How do we graph the function y = f(x) of an absolute equation?</h3>

The function of an absolute equation can be graphed by determining the values of x-intercepts and the y-intercepts of the function.

From the given equation:

y = 2|x+3| - 4

To determine the y-intercepts, we need to set the values of x to zero, and vice versa for x-intercepts.

By doing so, the x-intercepts and the y-intercepts of the function is:

  • x-intercepts = (-5,0) and (-1,0)
  • y-intercepts = (0,2)

Therefore, since we know the x and y-intercepts, the graph of the absolute value can be seen as plotted below.

Learn more about determining the graph of an absolute equation here:

brainly.com/question/2166748

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8 0
2 years ago
Show that area under multivariate normal distribution over the whole range in unity. Find characteristics function of multivaria
kenny6666 [7]

Answer:

here is the answer

Step-by-step explanation:

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8 0
3 years ago
I need help n explainnnn please ​
kobusy [5.1K]

The Correct option is D). y=1x+1 And y=2x+2

Step-by-step explanation:

The equation of a line is given as y=mx+c.

where m=slope of line and c=y intercept

The slope of line is given as  m=\frac{(Y2-Y1)}{(X2-X1)}

Solving for Redline:

From the given graph, redline passes through (-1,0) and (0,1)

The slope of Redline is  m=\frac{(Y2-Y1)}{(X2-X1)}

The slope of Redline is  m=\frac{(1-0)}{(0-(-1))}

The slope of Redline is  m=(1)

And Y-intercept is 1

The equation of a Redline is given as y=1x+1

Solving for Blue-line:

From the given graph, Blue-line passes through (-1,0) and (0,2)

The slope of Blue-line is  m=\frac{(Y2-Y1)}{(X2-X1)}

The slope of Blue-line is  m=\frac{(2-0)}{(0-(-1))}

The slope of Blue-line is  m=(2)

And Y-intercept is 2

The equation of a Blue-line is given as y=2x+2

The Correct option is D). y=1x+1 And y=2x+2

7 0
3 years ago
Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located
arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}&#10;\\\\&#10;c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\&#10;-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}&#10;\\\\\\&#10;csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

3 0
3 years ago
HELP ASAP PLEASE!!!!!
kiruha [24]
I think the answer is (6,-4)
5 0
3 years ago
Read 2 more answers
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