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vladimir1956 [14]
3 years ago
5

Determine the x-intercepts and y-intercepts for the following equation: –5x+2y- 10 = 0

Mathematics
2 answers:
Reptile [31]3 years ago
7 0

Answer:

x=2/5 y−2

Step-by-step explanation:

elixir [45]3 years ago
7 0

Answer:

x-intercepts = (-2,0)

y-intercepts = (0,5)

Step-by-step explanation:

First, make the equation into slope-intercept form. (y=mx+b)

y=5/2x+5

b= the y-intercept so <u>y-intercept = 5.</u>

If you graph this line, you can see that the <u>x-intercept = -2. </u>

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vivado [14]

Answer:

Step-by-step explanation:

(-6,-5) , ( 0,-1)  , (-3 , -3) , (2 , 0 ) are solution of the inequalities.

The point that lies on the purple area and on the solid line are the solutions of the equations.

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2 years ago
Need answer urgently please will give thanks and mark Brainliest
babymother [125]

Answer:

D

Step-by-step explanation:

sqrt(7) = about 2.6

and that divided by 2 is

0.8  which means D is the Answer

8 0
2 years ago
Ellen bought 3 greeting cards for $3 each.
Ne4ueva [31]

Answer:

(3×3)+2=11

$11

Step-by-step explanation:


5 0
3 years ago
18)Write 4 expressions that are equivalent to 6(c<br> 5) - 6?
Vikki [24]

Answer:

the answer is 6C+24 or if you divide 6 on both sides c+4

examples/expressions:

1. 4(1.5c+6)

2. 3(2c+8)

3. 2(3c+12)

4. 12(0.5c+2)

4 0
2 years ago
a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

8 0
3 years ago
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