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antoniya [11.8K]
4 years ago
6

Z-m=z+bx what equation do you get when you solve for x

Mathematics
1 answer:
SIZIF [17.4K]4 years ago
6 0
X = -m/b.
Subtract z from both side and you get
-m= bx
Now divide both side by b and you get
-m/b= x
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3(x 1) - 2x = -6 <br> a. x = 1 <br> b. x = 5 <br> c. x = -7 <br> d. x = -9
goblinko [34]
Your problem did not have an operator between the x and 1 so I did it as subtraction and addition. There was no answer choice -3 so D x=-9 is the answer

7 0
4 years ago
164 is 55% of what number?<br><br> Please somebody help me
monitta
This is how you solve it; but first of all convert the percent into a decimal;55%= 0.55

0.55x = 164 (divide by 0.55 on both sides)
x = 164/0.55 
x = 298.18 (rounded to the nearest hundredth)
so 164 is 55% of 298.18(rounded)
8 0
4 years ago
Asap help 100 points
gregori [183]

Answer:

(4x + 2)° = (6x -10)°

4x + 2 = 6x - 10

4x -6x = -10 -2

-2x = -12

x = <u>-</u><u>12</u>

-2

x = 6°

7 0
3 years ago
Read 2 more answers
Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. Th
zvonat [6]

The labor fee is $13.55 and each quart of oil is $2.25

Step-by-step explanation:

Let,

x be the amount of each quart of oil

y be the amount of labor fee

According to given statement;

5x+y=24.80        Eqn 1

7x+y=29.30        Eqn 2

Subtracting Eqn 1 from Eqn 2

(7x+y)-(5x+y)=29.30-24.80\\7x+y-5x-y=4.50\\2x=4.50

Dividing both sides by 2

\frac{2x}{2}=\frac{4.50}{2}\\x=2.25

Putting x=2.25 in Eqn 1

5(2.25)+y=24.80\\11.25+y=24.80\\y=24.80-11.25\\y=13.55

The labor fee is $13.55 and each quart of oil is $2.25

Keywords: linear equation, subtraction

Learn more about subtraction at:

  • brainly.com/question/116715
  • brainly.com/question/11680012

#LearnwithBrainly

6 0
3 years ago
PLEASE HELP , TRYING TO BE ON HONOR ROLL !
borishaifa [10]

Option A

The solution is (0, \frac{-1}{4})

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

3x + 6y = 1 ------ eqn 1

x - 4y = 1 ------ eqn 2

We have to find solution to system of equations

We can use substitution method

From eqn 2,

x = 1 + 4y -------- eqn 3

Substitute eqn 3 in eqn 1

3(1 + 4y) + 6y = 1

3 + 12y + 6y = 1

18y = 1 - 3

18y = -2

Divide both sides by 18

y = \frac{-2}{18}\\\\y = \frac{-1}{4}

Substitute the above value of y in eqn 3

x = 1 + 4 \times \frac{-1}{4}\\\\x = 1-1\\\\x = 0

Thus solution is (0, \frac{-1}{4})

8 0
3 years ago
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