We want to find the mean of two elements in a set, given that we know the other elements of the set and the mean of the whole set.
The answer is: -490
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For a set with N elements {x₁, x₂, ..., xₙ} the mean is given by:
Here we know that:
- The mean of the set is 0.
- The set has 1000 elements.
- 998 of these elements are ones, the other two are A and B.
We want to find the mean of the values of A and B.
First, we can start by writing the equation for the mean:
We can rewrite this as:
And we have 998 ones, then:
Now we have B isolated.
With this, the mean of A and B can be written as:
So we can conclude that the mean of the other two numbers is -490.
If you want to learn more, you can read:
brainly.com/question/22871228
Price of Brand A toothpaste for 17.4 ounces = <span>$5.22
</span>Price of Brand A toothpaste for 1 ounce = $5.22/17.4 = 0.3
Price of Brand B toothpaste for 26.6 ounces = $6.65
Price of Brand B toothpaste for 1 ounces = $6.65/26.6 = 0.25
So, if we see the price for per ounce of brand A and B, price of Brand B per ounce is less than brand A.
and if we find the difference between the prices of both = 0.3 - 0.25 = 0.05
Thus, the correct answer is "D", <span>Brand B is the better deal, because it costs $0.05 less per ounce than Brand A".</span>
Solution:
Let each pond of jelly beans cost $x.
and each pond of almonds cost $y.
Then we can write
Now solve these two equations together using substitution we get
Hence each pond of jelly bean cost 1.25$
Each pond of almond costs 2.25$
Answer:
The probability that neither is available when needed
Step-by-step explanation:
A town has 2 fire engines operating independently
Given data the probability that a specific engine is available when needed is 0.96.
Let A and B are the two events of two fire engines
given P(A and B) = 0.96 ( given two engines are independent events so you have to select A and B)
Independent events : P( A n B) = P(A) P(B)
The probability that neither is available when needed
1) A: The first table
2) B: The water level increases by 2 inches each hour.
Hope this helps
