Answer:
C. 0
Step-by-step explanation:
–4j^2 + 3j – 28 = 0
The discriminant is b^2-4ac if >0 we have 2 real solutions
=0 we have 1 real solutions
<0 we have 2 imaginary solutions
a = -4, b =3 c = -28
b^2 -4ac
(3)^2 - 4(-4)*(-28)
9 - 16(28)
9 -448
This will be negative so we have two imaginary solutions.
Therefore we have 0 real solutions
(f-g)(x) will be 3x^2 -2x+4 -(5x^2+6×-8)
distribute the -sign, gives us
3x^2-2x+4-5x^2-6x+8,
now combine like terms and should get,
-2x^2-8x+12,
final answer,
(f-g)(x)= -2x^2-8x+1×,
hope it helped,
good luck
Answer:
I think A. Reflexive Property but if I am wrong, I am so sorry
Step-by-step explanation:
because 6 + 1 is is not subtracting or multiplying
Hope this helps
