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Sphinxa [80]
3 years ago
15

Identify the center and radius of a circle with equation (x+4)^2+(y-2)^2=36

Mathematics
1 answer:
Kitty [74]3 years ago
3 0
In the equation of a circle in the form (x-h)^2 + (y-k)^2 = r^2, (h,k) is the center and r is the radius.

So, the center of the circle is at (-4,2) with radius 6 units.
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In ΔXYZ, the measure of ∠Z=90°, ZY = 4, XZ = 3, and YX = 5. What ratio represents the tangent of ∠X?
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marishachu [46]
I’m guessing you want to find out (n).
That’s what I did anyway.

The answer is: n=5

Step 1: Subtract 5n from both sides.
3.2
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+
9
−
5
n
=
5
n
−
5
n
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1.8
n
+
9
=
0
Step 2: Subtract 9 from both sides.
−
1.8
n
+
9
−
9
=
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9
−
1.8
n
=
−
9
Step 3: Divide both sides by -1.8.
−
1.8
n
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1.8
=
−
9
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7 0
3 years ago
What are the coordinates of N?
Nataliya [291]

Answer:

(c,b) are the coordinates of N

Step-by-step explanation:

as N is the mid-point of QR

BY USING MID-POINT FORMULA

N(x,y)=(\frac{x1+x2}{2},\frac{y1+y2}{2})

PUTTING THE VALUES OF COORDINATES

N(x,y)=(\frac{0+2c}{2},\frac{2b+0}{2})

N(x,y)=(\frac{2c}{2},\frac{2b}{2})

N(x,y)=(c,b) are the coordinates

O HOPE THIS WILL HELP YOU :)

5 0
3 years ago
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