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Sholpan [36]
3 years ago
6

Alan is putting weed killer on a field to get it ready for planting. The directions on the can say to use 4/5 of a quart for eac

h acre of land. How much weed killer will Alan need for two fields, one that is 22 1/2 acres and one that is 38 1/4 acres?
3. Draw a picture or a chart that shows the information and the question

28 1/8 quarts
47 4/5 quarts
60 3/4 quarts
48 3/5 quarts
Mathematics
1 answer:
Kazeer [188]3 years ago
3 0
(22.5+38.25)(4/5)=48.6 or 48 6/10=48 3/5 quarts
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I need help ASAP!!!!!
kupik [55]

Answer:

y = 50

Step-by-step explanation:

Firstly, let's make an equation. We know that when y is 15, x is 3. Or, in other words, y is 5 times what x is. Therefore we can use the equation, y = 5x.

Now, just plug x into the equation.

y = 5(10)

y = 50

5 0
3 years ago
Read 2 more answers
Use the divergence theorem to calculate the surface integral s f · ds; that is, calculate the flux of f across s. f(x, y, z) = x
valkas [14]
\mathbf f(x,y,z)=x^4\,\mathbf i-x^3z^2\,\mathbf j+4xy^2z\,\mathbf k
\mathrm{div}(\mathbf f)=\dfrac{\partial(x^4)}{\partial x}+\dfrac{\partial(-x^3z^2)}{\partial y}+\dfrac{\partial(4xy^2z)}{\partial z}=4x^3+0+4xy^2=4x(x^2+y^2)


Let \mathcal D be the region whose boundary is \mathcal S. Then by the divergence theorem,

\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV

Convert to cylindrical coordinates, setting

x=r\cos\theta
y=r\sin\theta

and keeping z as is. Then the volume element becomes


\mathrm dV=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz

and the integral is

\displaystyle\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=0}^{z=r\cos\theta+7}4r\cos\theta\cdot r^2\cdot r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle4\iiint_{\mathcal D}r^4\cos\theta\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\dfrac{2\pi}3
4 0
4 years ago
Describe the transformations of how the graph y=x^2 can be transformed into y= -1/5 (x-4)^2 + 2
Orlov [11]

Answer:

Reflected over the x-axis, vertically shrunk by a factor of 1/5, moved right 4 units and up 2 units.

Step-by-step explanation:

Parent Graph: f(x) = a(bx - h)² + k

<em>a </em>is vertical stretch (a > 1) or shrink (a < 1) and reflection over x-axis

<em>b</em> is horizontal stretch or shrink and reflection over y-axis

<em>h</em> is horizontal movement left (if positive) or right (if negative)

<em>k</em> is vertical movement up (if positive) or down (if negative)

Now that we have our rules, we simply apply it to y = -1/5(x - 4)² + 2

<em>a</em> = -1/5, so reflection over x-axis and vertical shrink of 1/5 (1/5 < 1)

Nothing has changed <em>b</em>, so no horizontal stretch/shrink

<em>h</em> = -4, so horizontal movement right 4 units

<em>k</em> = 2, so vertical movement up 2 units

8 0
3 years ago
Given real numbers a,b &gt; 1.
irina [24]

Answer:

FALSE

Step-by-step explanation:

Recall that a function f(x) is of exponential order c, if there exists a constant M such that and a real r such that

|f(x)|\leq Me^{cx}\;(x\geq r)

Now, take a = 2.5 and b = 2

The functions

f(x)=(2.5)^x\;g(x)=2^x

are both exponential of order 1, since  

\lim_{x \to \infty}\frac{f(x)}{e^x}=\lim_{x \to \infty}\frac{g(x)}{e^x}=0

but a>b

8 0
3 years ago
One of your friends is testing the effect of drinking coffee on the duration of cold symptoms. The common cold lasts, on average
Goshia [24]

Answer: 0.0930

Step-by-step explanation:

As per given , we have

H0: μcoffee = 6

Ha: μcoffee < 6

She finds z = −1.68 with one-sided P-value P = 0.0465.

The P-value for two-tailed test is calculated by :

2P(Z>|z|)

For z= -1.68 , we have

2P(Z>|-1.68|)=2P(Z>1.68)

=2(1-P(z\leq1.68))\ \ [\because\ P(Z>z)=1-P(Z\leq z)]

=2(1-0.9535213)\ \ \ [\text{ NORM.S.DIST(z, TRUE}]\\\\=2( 0.0464787)=0.0929573\approx0.0930  

Hence, the correct two-sided P-value for z = −1.68 is 0.0930 .

3 0
3 years ago
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