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SSSSS [86.1K]
2 years ago
8

if you have $280 and you have 12 months or 365 days to pay it off. how much money would you pay every month?

Mathematics
2 answers:
marshall27 [118]2 years ago
8 0

Answer:

23

Step-by-step explanation:

280/12=23.33333.............

elena-14-01-66 [18.8K]2 years ago
6 0

<u>Answer:</u>

We have to pay \$23.33 every month.

<u>Solution: </u>

Given that, the total amount we have is  \$280

We have total time = 12 months.

We need to find the amount needed to pay per month.

So, the total amount to be paid can be found by diving the total amount by total time.

Amount to be paid = \frac{\text {total amount}}{\text {total time}}

Therefore, \frac{\$ 280}{12} = 23.\overline{333333}

which is \approx \$23.33

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A random sample of 16 students selected from the student body of a large university had an average age of 25 years and a populat
eimsori [14]

Answer:

t=\frac{25-24}{\frac{2}{\sqrt{16}}}=2      

p_v =P(t_{15}>2)=0.0320  

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the true mean is significant higher than 24 years.  

Step-by-step explanation:

1) Data given and notation      

\bar X=25 represent the sample mean      

s=2 represent the standard deviation for the sample      

n=16 sample size      

\mu_o =24 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

Confidence =0.95 or 95%

\alpha=0.05

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean is higher than 24, the system of hypothesis would be:      

Null hypothesis:\mu \leq 24      

Alternative hypothesis:\mu > 24      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{25-24}{\frac{2}{\sqrt{16}}}=2      

Calculate the P-value      

First we need to calculate the degrees of freedom given by:  

df=n-1=16-1=15  

Since is a one-side upper test the p value would be:      

p_v =P(t_{15}>2)=0.0320  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the true mean is significant higher than 24 years.      

3 0
2 years ago
Find m∠BAC and m∠DAB in the figure shown below.
masha68 [24]
\angle BAC=\angle DAE=80^{\circ}\\&#10;\angle DAB=180-\angle BAC=180-80=100^{\circ}
8 0
2 years ago
Read 2 more answers
Which Expression is equivalent to 4(6 + x + 3x)
Gennadij [26K]

Answer:

=4(6) + 4(X) + 4(3x)

=24+4x+12x

=24+16x

7 0
2 years ago
What two consecutive integers does 20−−√ fall between?
Alex_Xolod [135]

Answer:

4 and 5

Step-by-step explanation:

8 0
2 years ago
Solve for x: -6(x + 4) + 9 &gt; -5(x + 6)
devlian [24]

Answer:

x < 15

Step-by-step explanation:

Let's first expand the parentheses on both sides. Remember that when expanding parentheses, the result will be the sum of the products of the "outside number" with each of the "inside number".

On the left, the parenthetical expression is: -6(x + 4). Here, the outside term is -6 and the inside terms are x and 4. So:

-6(x + 4) = -6 * x + (-6) * 4 = -6x - 24

On the right, the parenthetical expression is: -5(x + 6). Here, the outside term is -5 and the inside terms are x and 6. So:

-5(x + 6) = -5 * x + (-5) * 6 = -5x - 30

Now put these back in:

-6(x + 4) + 9 > -5(x + 6)

-6x - 24 + 9 > -5x - 30

-6x - 15 > -5x - 30

x < 15

Thus the answer is x < 15.

Hope this helps!

3 0
2 years ago
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