Let that be
Two vertical asymptotes at -1 and 0
If we simply
- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
Find zeros
Horizontal asymptote
So our equation is
Graph attached
Answer: 4/3
Step-by-step explanation:
You would find this answer because if x is 0 then it is just 2 then when you multiply 3 x 4/3 you get 4 then when you add that by two you get 6
Hopes this helps
Answer:
slope 1.5, passes through (0, 5) 62/87,21 Substitute m = 1.5 and ( x, y) = (0, 5) in the equation y
Step-by-step explanation:
boom
9514 1404 393
Answer:
a = 1
Step-by-step explanation:
The slope of the inverse of a linear function is the inverse of the slope of the original function.
The slope of g(x) is the coefficient of x: 1.
The inverse of 1 is 1/1 = 1.
The slope of the function g^-1(x) is 1, so a=1.
_____
<em>Additional comment</em>
g^-1(x) = x +65 . . . . . a=1; b=65
Answer:
63/4
Step-by-step explanation:
i think
