PLEASE HELP QUICKLY OFFERING 98 POINTS WILL MARK BRAINLIEST
2 answers:
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ΔJKL, sin(JLK)=JK/KL=3/6=0.5
<JKL=30deg.
cos(JLK)=JL/KL
JL=KL*cos(JLK)=6cos(30deg.)
<JLK + <JLM = <MLK
30 + <JLM = 61
<JLM=31deg
in ΔMJL
tan(JLM)=JM/JL
JM=JL*tan(JLM)
=6cos(30deg.)*tan(31deg)
=3.12
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