to the right of the garden draw a different shape that has the same perimeter as part A of elton's garden what is the area of yo
2 answers:
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This is a doozy so pay attention. First thing you have to recognize is that is a trig identity, the sum identity for cosine to be exact. That formula is
.
So that means you need to find the cosine of alpha and the sin of beta. We are given the sin of alpha being 4/5 in the first quadrant. If you set up the sin ratio which is side opposite over hypotenuse of a right triangle, you put the 4 on the side opposite the reference angle, alpha, and the hypotenuse of 5 on the terminal ray and then you have to find the missing side of the right triangle you created. Using Pythagorean's theorem, you find that the missing side, which is the adjacent side to alpha, is 3. Now you can find the cosine of alpha as well, since cosine is the side adjacent, 3, over the hypotenuse, 5. So far wwe have
and
for that first angle. Now moving on to the second angle. The cosine of beta is side adjacent, 5, over the hypotenuse, 13, and we are missing the side opposite the reference angle beta. Using Pythagorean's theorem again to find the side opposite, we have that that side measures 12. Now we can find the sine of beta using that opposite side, 12, over the hypotenuse, 13. What we have now is
and
. According to the identity, we have to multiply those ratios now:
.
When you do that you get
.
Of course in order to subtract those 2 fractions you need a common denominator which is 65 so
which gives you a final answer of
which is the first choice given above. There you go!
Answer:
When we have a given function, y = f(x), the general way of graphing the function is finding a lot of coordinate pairs (x, f(x)) and graphing them in a coordinate axis, and then connect them.
So here we have:
p(x) = 2x^(3)+7x^(2)-3x-18
Just let's find the value of p(x) for different values of x, and let's do it.
p(0) = 2*0^(3)+7*0^(2)-3*0-18 = -18
Then the point (0, -18) belongs to the graph
p(1) = 2*1^(3)+7*1^(2)-3*1-18 = 2 + 7 - 3 - 18 = -12
then the point (1, - 12) belongs to the graph.
p(-1) = 2*(-1)^(3)+7*(-1)^(2)-3*(-1)-18 = -2 + 7 + 3 - 18 = -10
then the point (-1, -10) belongs to the graph:
p(2) = 2*2^(3)+7*2^(2)-3*2-18 = 16 + 28 - 6 - 18 = 20
Then the point (2, 20) belongs to the graph
p(-2) = 2*(-2)^(3)+7*(-2)^(2)-3*(-2)-18 = -16 + 28 + 6 - 18 = 0
Then the point (-2, 0) belongs to the graph.
p(-3) = 2*(-3)^(3)+7*(-3)^(2)-3*(-3)-18 = -54 + 63 + 9 - 18 = 0
Then the point (-3, 0) belongs to the graph.
Now that we have 6 points we can graph them and try to connect them.
We also know that this is a cubic polynomial, so we can expect that it changes its direction two times (no more than that) then knowing that we can estimate a shape for the graph, and you will obtain something like the graph of the image below, where I just connected the known points.
Answer:
£714.00
Step-by-step explanation:
The first step is to set up expresssions for the two shares:
Let x = the amount of one share. The other share is 1785 - x. <u>You don't have to worry about which is smaller--that part will work out automatically</u>!
The two shares are in the ratio of 2:3, so set up the proportion
Again, you don't have to worry--you could set up the proportion "upside down" and everything will work out in the end.
Solve the proportion for x by "cross multiplying" -- use the Means-Extremes Property of proportions.
So one share is £714£ and the other is £1785 - £714 = £1071.
The smaller share is £714.
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