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Alexxx [7]
3 years ago
12

The heights (in cm) and arm spans (in cm) of 31 students were measured. The association between x(height) and y(arm span) is sho

wn in the scatterplot below. The equation of the line of best fit modeling this relationship is given.
Y=4.5x + 0.977x

Mike is 175cm tall and George is 170cm tall.
Using the model, how many centimeters longer would we expect Mike's arm span to be than George's?

____Cm

Mathematics
1 answer:
abruzzese [7]3 years ago
8 0

Answer:

27.385 cm longer would we expect Mike's arm span to be than George's.

Step-by-step explanation:

We have to find how many centimeters longer would we expect Mike's arm span to be than George's using the equation:

y= 4.5x + 0.977 x

where y= arm span

and x= height

Given:

Mike's height=x = 175 cm

so Mike's arm span= y= 4.5 x + 0.977 x

                                    = 4.5* (175) + 0.977* (175)

                                    = 787.5 + 170.975

                                    = 958.475 cm

George's height = x = 170 cm

so George's arm span= y= 4.5 x + 0.977 x

                                    = 4.5* (170) + 0.977* (170)

                                    = 765 + 166.09

                                    = 931.09 cm

Mike's arm span longer than George's = Mike's arm span - George's arm span

                                                                 = 958.475 - 931.09

                                                                 = 27.385 cm.

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Answer:

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No. of girls in the school = 280

The ratio boys to girls is 3:4 and that of teachers to girls is 1:7

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Step-by-step explanation:

Given: (4z^2+7z-8)(-z+3)=-4z^3+xz^2+yz-24; find x and y.

Let's start with finding x first. Let's distribute the left side of the equation.

-4z^3+5z^2+29z-24=-4z^3+xz^2+yz-24

Let's move everything we can to the left side of the equation. Some things will cancel out.

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Now, let's move the term that includes x to the left side of the equation. Everything else should be moved to the right.

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Let's get rid of the negative sign in front of x by dividing both sides by -1.

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To get x completely isolated, divide both sides by z^2.

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yz=5z^2+29z-xz^2

To isolate y, divide both sides by z.

\frac{yz}{z}=\frac{5z^2}{z}+\frac{29z}{z}-\frac{xz^2}{z}

Simplify.

y=5z+29-xz

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