Answer:
a) 0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.
b) 0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.
Step-by-step explanation:
Question a:
20% of employees engage in physical exercise.
This 20% is composed by:
8% of 60%(males)
x% of 100 - 60 = 40%(females).
Then, x is given by:




0.38 = 38%
Probability of being a female who engages in exercise:
40% are female, 38% of 40% engage in exercise. So
0.38*0.4 = 0.152
0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.
B. If we choose an employee at random from this corporation,what is the probability that this person is a female who does not engage in physical exercise activities during the lunch hour?
40% are female, 100% - 38% = 62% of 40% do not engage in exercise. So
0.62*0.4 = 0.248
0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.
Answer:
a. Relative Growth rate = 10% (6/60 * 100)
b. Number of cells after t hours = 50 * 1.1^t
c. Rate of growth after 6 hours = 77.2% (1.1⁶ - 1)
d. The number of cells after 6 hours is
= 89 cells
Step-by-step explanation:
A cell divides into two cells every 20 minutes
In one hour, the cell will divide into 60/20 * 2 = 6 cells
Each cell growth 6 cells per hour
Initial population of a culture = 50 cells
t = time in hours
a. Relative Growth rate = 10% (6/60 * 100)
b. Number of cells after t hours = 50 * 1.1^t
c. Rate of growth after 6 hours = 77.2% (1.1⁶ - 1)
d. The number of cells after 6 hours = initial population * growth factor
= 50 * 1.772
= 88.6
= 89 cells
It would be 3 with be on the side and then 2/10
Answer:179
/20
(Decimal: 8.95)
Step-by-step explanation:
2+3+4−
5
/100
=5+4−
5
/100
=9−
5
/100
=9−
1
/20
=
179
/20