Use the distributive property to model the product on the grid 4x12=

Use the quadratic formula to find the solutions to the quadratic equation below 2x^2-5x+5=0

Serggg [28]

Answer:

x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4

Step-by-step explanation:

Solve for x:

2 x^2 - 5 x + 5 = 0

Hint: | Using the quadratic formula, solve for x.

x = (5 ± sqrt((-5)^2 - 4×2×5))/(2×2) = (5 ± sqrt(25 - 40))/4 = (5 ± sqrt(-15))/4:

x = (5 + sqrt(-15))/4 or x = (5 - sqrt(-15))/4

Hint: | Express sqrt(-15) in terms of i.

sqrt(-15) = sqrt(-1) sqrt(15) = i sqrt(15):

Answer: x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4

5 0

3 years ago

Evaluate the function at the indicated values if possible. If an indicated value is not in the domain, say so.

goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

$f(x)=\frac{x+7}{x^2-9}$ is the given function.

We are asked to find:

$f(-7)$

$f(2)$

$f(3)$ .

f(-7) means to replace x in the expression called f with -7:

Evaluate $\frac{x+7}{x^2-9}$ at $x=-7$

$\frac{(-7)+7}{(-7)^2-9}$

$\frac{0}{49-9}$

$\frac{0}{40}$

$0$

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate $\frac{x+7}{x^2-9}$ at $x=2$

$\frac{2+7}{2^2-9}$

$\frac{9}{4-9}$

$\frac{9}{-5}$

$\frac{-9}{5}$

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate $\frac{x+7}{x^2-9}$ at $x=3$

$\frac{3+7}{3^2-9}$

$\frac{10}{9-9}$

$\frac{10}{0}$

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0

3 years ago

Please help me with my question!!

Dmitrij [34]

The question is unclear but I will assume they mean 1/4 and 3 1/2.

Find common denominators.

1/4

3 1/2 -> 3 2/4

Turn into an improper fraction.

3 2/4 -> 14/4

Divide.

14/4 / 1/4

14/4 * 4/1

56/4

14

So, they can make 14 ornaments.

Best of Luck!

6 0

3 years ago

dilation the center of dilution is the origin b (2,3) and B(-4,-6) what is the scale factors of this dilation that transformed a

Ann [662]

Given:

Consider the two points are B(2,3) and B'(-4,-6).

Center of dilation is the origin.

To find:

The scale factors of this dilation that transformed B into B'.

Solution:

If a figure dilatated by scale factor k and center of dilation is the origin, then

$(x,y)\to (kx,ky)$

It means, the point after dilation is

$(x',y')=(kx,ky)$

where, k is the scale factor.

$k=\dfrac{x'}{x}$

x-coordinate of image is -4 and x-coordinate of original point is 2.

$k=\dfrac{-4}{2}$

$k=-2$

Therefore, the scale factor is -2. It means, the point and image lie on the opposite sides of center of dilation.

3 0

3 years ago

Starrla was trying to collect 3 pounds of cans to recycle. If she collects one-fourth of a pound each day, how many days will it

joja [24]

Answer:

32

Step-by-step explanation:

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4 0

3 years ago