Question

18 Which shows the equation 2x - 8y = -16 in slope-intercept form?

Answer 1

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$2x - 8y = - 16$

Subtract sides 2x

$- 2x + 2x - 8y = - 2x - 16$

$- 8y = - 2x - 16$

Negatives simplifies

$8y = 2x + 16$

Divide sides by 8

$\frac{8y}{8} = \frac{2x + 16}{8}$

$y = \frac{2}{8} x + \frac{16}{8}$

$y = \frac{1}{4} x + 2$

Done...

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