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Irina18 [472]
3 years ago
11

Evaluate the numerical expression:(-⅓)-(-⅖)=?​

Mathematics
2 answers:
NeTakaya3 years ago
7 0

Answer:

1/15

Step-by-step explanation:

notsponge [240]3 years ago
7 0

Answer:

1/15

Step-by-step explanation:

Lets simplify, since we need to account for the double negative:

-1/3 + 2/5 = 1/15

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If a person bikes 6 miles in 15 minutes, how far can she bike in 1.5 hours?
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Answer:

36\:miles

Step-by-step explanation:

There is <em>one-and-a-half</em> <em>hour</em> in <em>ninety</em><em> </em><em>minutes</em>,<em> </em>so multiply 6 by 15 to get 90, then whatever is done to the bottom is also done to the top, so you <em>square</em> 6 to get 36.

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3 years ago
How many solutions does the system have?<br> 8x + 2y = 14<br> (8x + 2y = 4
e-lub [12.9K]

Answer:

zero

Step-by-step explanation:

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3 years ago
What are the x- and y-intercepts of the graph of y = x2 + 3x − 10? (1 point)
Lynna [10]

Answer:

x-intercepts: (2, 0) and (−5, 0)  

y-intercept: (0, −10)

Step-by-step explanation:

y = x^2 + 3x − 10

y-intercept when x = 0 so y = -10, so y-intercept : (0, -10))

x-intercept when y = 0 so

x^2 + 3x − 10 = 0

(x +5)(x - 2) = 0

x + 5 = 0; x = -5

x - 2 = 0; x = 2

So x-intercepts: (-5, 0) and (2,0)

7 0
3 years ago
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Step-by-step explanation:

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Read 2 more answers
Solve the system or linear equations
Vanyuwa [196]

Answer:

37. {-1, -1}.

Step-by-step explanation:

I'll solve the first one . The other can be solved in a similar way. We can use the method of elimination.

x1 - x2 = 0

3x1 - 2x2 = -1

We can multiply the first equation by -2. We then have an equation containing + 2x2 so when we add this to the second equation the 2x2 will be eliminated

So the first equation becomes:

-2x1 + 2x2 = 0     Bring down the second equation:

3x1 - 2x2 = -1       Now adding, we get:

x1 + 0 = -1

so x1 = -1.

Now we substitute this value of x1 in the original first equation:

-1 - x2 = 0

-1 = x2

x2 = -1.

So the solution set is {-1, -1}.

If there are more than 2 equations you can use a combination of substitutions and eliminations.

8 0
3 years ago
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