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2 years ago

10

claudio will decorate his bedroom he can choose tan, blue, or gray paint and striped or plaid curtains how many ways can he deco

rate his room with different paint and curtains

1 answer:

Orlov [11]2 years ago

4 0

5×5×5×5×5=3125

3,125 ways he can decorate his room with different paint and curtains.

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A survey of students at a university shows that 4 out of 5 drink coffee. Of the students who drink coffee, 1 out of 6 adds crea

Andru [333]

The number who drink coffee is 3/4 of 8000, so ...
... (3/4)×8000 = 6000.
Of those, 1/5 add cream, so the number of coffee drinkers who add cream to their coffee is ...
... (1/5)×6000 = 1200.
_____
Alternate solutions
We have computed ...
... (1/5)×((3/4)×8000) = 1200
Since multiplication is associative, you can multiply the fractions first, if you wish:
... ((1/5)×(3/4))×8000 = (3/20)×8000
... = 24000/20 = 1200
or
... = 3×(8000/20) = 3×400 = 1200

6 0

2 years ago

.<br> Find angle Z<br> 25 km side <br> 23 km side <br> 28 km side

Savatey [412]

You don’t have a picture

6 0

2 years ago

If sin^2(x) - 2sin(x) = 2, then sin(x) = _____.

alekssr [168]

Let z = sin(x).
.. z^2 -2z = 2
.. z^2 -2z +1 = 3
.. (z -1)² = 3
.. z -1 = ±√3
.. z = 1 -√3 . . . . . the positive solution is extraneous

sin(x) = 1 -√3

3 0

2 years ago

Which list correctly orders A, B, and C from least to greatest when A= |7|, B = _6, and C = |-5|?

zheka24 [161]

Answer:

D. B,C,A

Step-by-step explanation:

A= |7|=7

B= -6

C= |-5|=5

so this means that B<C<A = -6<5<7

so; B,C,A = -6,7,5

8 0

2 years ago

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

2 years ago