The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation 
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2=0
=> =0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
#SPJ1
Answer: -4
Step-by-step explanation:
F=3; f=7 hope this helps !
<h3><u>Answer</u> :</h3>
For triangle : A + B + C = π
⇒ A + B = π - C
⇒ cot(A + B) = cot(π - C)
⇒ 
⇒ 
<u>Now 1st part of the given expression</u>!
⇒ 
⇒ 
⇒ 
⇒ 1 - cotB cotC
<u>Similarly 2nd part</u>!
⇒ 1 - cotA cotB
<u>Similarly 3rd part</u>!
⇒ 1 - cotC cotA
<u>LHS</u> :
= <u>RHS</u>
<h3>Hence Proved!!</h3>
Answer:
C
Step-by-step explanation:
Midpoint is like average, so 0+20 (the x-coordinates) = 20, then divide it by 2 to get the midpoint.
I hope this helped, and please mark this as brainliest!
