3 years ago

Which ordered pair is a solution of the equation? y=8x+3y=8x+3

Mathematics

2 answers:

jeyben [28]3 years ago

7 0

y=8x+3y=8x+3

the answer is (7,4) i think

_queenshadygucci_

Mrac [35]3 years ago

3 0

Multiply the first equation by 4 (so that both equations will have 8x terms) and then subtract:

8x-20y = -24

8x +3y = 68

------------

0 -23y = -92

Now divide both sides by -23:

y = 4

Find x by plugging y=4 into either equation:

8x +3(4) = 68

8x = 68 - 12

8x = 56

x = 7

So the answer is ordered pair is (7,4)

You might be interested in

Molly works at an aple orchard.she picked 1,078 apples last weekend and put them into bags that hold 12 apples each.how many bag

Crazy boy [7]

She filled 89 bags with 10 apple remaining

8 0

3 years ago

3 + 5x = 5(x + 2) -7

Anna35 [415]

Answer:9283022

Step-by-step explanation:

00292+20283+22928+sike

4 0

3 years ago

The width of a rectangle is four units less that its length. Write an expression for the perimeter of the rectangle

Hunter-Best [27]

(2w-8)+2L because there are 2 sides for the width 2*4=8 so 2w -8 plus 2L

5 0

2 years ago

Consider the following system of equations, <br> −2x−9y=12−2x−7y=8 <br> The value of x is

joja [24]

The value of x is 23 and the value of y is -6

x = 23

y = -6

You're welcome.

6 0

3 years ago

Rationalize the denominator and simplify.

Irina18 [472]

Answer:

$\frac{3 \sqrt{2} - 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } \times \frac{3 \sqrt{2} - 2 \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \\ \\ = \frac{18 + 12 - 12 \sqrt{6} }{18 - 12} \\ \\ = \frac{30 - 12 \sqrt{6} }{6} \\ \\ = 5 - 2 \sqrt{6}$

7 0

3 years ago