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Bas_tet [7]
3 years ago
15

What is the perimeter of the following figure

Mathematics
1 answer:
tester [92]3 years ago
4 0

Answer:

13

Step-by-step explanation:

7 cm +1 cm +2cm +2cm :12cm

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Sandra calculated the height of a cylinder that has a volume of 576(pie) cubic centimeters and a radius of 8 centimeters. Her wo
mr_godi [17]

Answer:

See below.

Step-by-step explanation:

Step 3 should be: 576pi / 64pi = 64pi h / 64pi

Step 4:  9 = h.

I would say C and D.

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Which explains how to find the quotient of the division below? - 3 1/3 divided by 4/9 Write Negative 3 and one-third as Negative
makvit [3.9K]

Answer:

its B

Step-by-step explanation:

cuz -3 1/3 would be turned into -10/3 by multiplying 3*3 which will give u 9 and adding 1 which is 10 then u put the 10 on top and keep the 3 as bottom.

and then flip the 4/9 which will turn into 9/4 so now u can multiple intead of divide

-10/3 * 9/4 and then youll get ur answer.

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3 years ago
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What four fractions can be made with the cards that have values less than 12
Oksanka [162]

Answer:

4/8 3/6 5/10 2/4 6/12

Step-by-step explanation:

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8 0
3 years ago
A soccer player kicks a ball downfield. The height of the ball increases until it reaches a maximum height of 8 yards, 20 yards
Agata [3.3K]

Answer:

  • second kick goes farther
  • first kick goes higher

Step-by-step explanation:

Assuming the kick started from ground level, the path of the ball is assumed to be symmetrical about the high point. That is, the first kick will land 2×20 = 40 yards downfield.

The equation for the second kick can be rewritten as ...

  y = 0.008x(50 -x)

The value of y will be zero at x=0 and at x=50. The second kick will land 50 yards downfield, a greater distance than the first kick.

At x=25, the height of the second kick is ...

  y = 0.008(25)(50-25) = 5 . . .  yards

The second kick travels farther (50 yds vs. 40 yds).

The first kick travels higher (8 yds vs. 5 yds).

8 0
3 years ago
Select the correct answer from each drop-down menu. ∆ABC has vertices at A(11, 6), B(5, 6), and C(5, 17). ∆XYZ has vertices at X
Vika [28.1K]

The option  that is shown to be congruent by a sequence of reflections and translations is Option B: Triangle ABC and Triangle MNO

  • Option  C:  Triangle JKL and Triangle PQR can be shown to be congruent by a single rotation.

<h3>How are they congruent?</h3>

Note that:

If ∆MNO  can be gotten  from ∆ABC  then ∆MNO ≅ ∆ABC  

To solve for Reflection (x axis), it will be:

The coordinate note for the reflection is (x, y) will be: (x,-y)

Since ∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).

Then the reflections will be:

M(-9, -4)- M1(-9,4)

N(-3, -4)- N1(-3,4)

O(-3,-15)-O1(-3,15)

To solve for Reflection (y axis), it will be:    

The coordinate note for the Reflection  is (x,y) will be (-x,y)

Since ∆M1N1O1  = M1(-9, 4), N1(-3, 4), and O1(-3, 15).

Then M1(-9, -4) - M2(9,4)

N1(-3, -4) - N2(3,4)

O1(-3,-15)- O2(3,15)

To solve for Translation

The coordinate note for the Translation is (x,y) will be (x+2,y+2)

Since ∆M2N2O2  = M2(9,4), N2(3,4), and O2(3, 15).

Then M2(9, 4) - M3(11,6)=A

N2(3,4) -  N3(5,6)=B

O2(3,15) - O3(5,17)=C

Hence  ∆MNO ≅ ∆ABC  

To know the congruent by a single rotation.

 If ∆JKL  can be gotten from ∆PQR

Then ∆JKL ≅ ∆PQR  

For Rotation of 90 degree in an anticlockwise position, then:

The coordinate note for the Rotation is (x,y) will be (-y, x)

So, ∆JKL  = J(17, -2), K(12, -2), and L(12, 7).

J(17, -2)-  J1(2,17)

K(12, -2) - K1(2,12)

L(12,7) - L1(-7,12)

To solve for translation

The coordinate note for the translation is (x,y) will be (x+10,y-14)

Then ∆J1K1L1 =  J1(2, 17), K1(2, 12), and L1(-7, 12).

Hence J1(2, 17) - J2(12,3) = P

K1(2, 12)- K2(12,-2) = Q

L1(-7, 12)- L2(3,-2) = R

So, ∆JKL ≅ ∆PQR.

So therefore, The option  that is shown to be congruent by a sequence of reflections and translations is Option B: Triangle ABC and Triangle MNO

  • Option  C:  Triangle JKL and Triangle PQR can be shown to be congruent by a single rotation.

See options below

___ can be shown to be congruent by a sequence of reflections and translations.

1)Pick one to go with the sentence.

a Triangle ABC and Triangle XYZ

b Triangle ABC and Triangle MNO

c Triangle JKL and Triangle ABC

d Triangle PQR and Triangle XYZ

___ can be shown to be congruent by a single rotation.

Pick one to go with the sentence.

a Triangle ABC and Triangle XYZ

b Triangle PQR and Triangle XYZ

c Triangle JKL and Triangle PQR

d Triangle JKL and Triangle XYZ

Learn more about congruent angles from

brainly.com/question/8531982

#SPJ1

3 0
1 year ago
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