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lilavasa [31]
3 years ago
11

Solve each inequality and graph its solution .. 40 points and brainlyest will be awarded

Mathematics
1 answer:
OLga [1]3 years ago
5 0

Answer:

sorry but i really need

points

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2b to the power of 2 = 100 i want to know if this question is true or false, someone help me pleaseee.
OLEGan [10]

Answer

5

Step-by-step explanation:

10^2= 100

so b must be 5

6 0
3 years ago
Erin is making fruit salad.For each bowl of fruit salad,she needs 2/3 cup of strawberries.How many cups will she use if she make
grigory [225]
She needs 18 times of 2/3 cup, this is

18\cdot \frac{2}{3}=12 cups
5 0
4 years ago
Read 2 more answers
What does 5/7c=13/14 equal
natita [175]
To find c, you must isolate it.
To do this, you must divide both sides by 5/7, since that is being multiplied by c and you must do the inverse to it to cancel it out in order to leave c by itself.

5/7c ÷ 5/7 = c

13/14 ÷ 5/7
To divide fractions, follow these steps:
Step 1- Turn the second fraction, 5/7 in this case, into its reciprocal. This means swapping the places of the numerator and denominator.
5/7 reciprocal = 7/5

Step 2- multiply the original first fraction and reciprocal second fraction.
13/14 • 7/5
13 • 7 = 91
14 • 5 = 70
13/14 ÷ 5/7 = 91/70

Step 3- Simplify if possible.
91/70
Since 70 can go into 90, you can turn this into a mixed number.
1 and 21/70
Now simplify 21/70.
Both can be divided by 7.
21 ÷ 7 = 3
70 ÷ 7 = 10
So simplified, 91/70 equals 1 and 3/10.
As a decimal, this is 1.3.

So the answer is c = 1.3, or 1 and 3/10.

Hope this helps :)
8 0
4 years ago
If f(x)=x^1/2 and g(x)=2x^3-x^1/2, find f(x)-g(x)... HELP ITS URGENT
bija089 [108]
F(x) - g(x) =
x^1/2 - (2x^3 - x^1/2)=
x^1/2 - 2x^3 + x^1/2=
2x^1/2 - 2x^3
7 0
3 years ago
Find the range of the given data set.<br> -4, -3, -1, -1, 0, 1
Vika [28.1K]

Answer: 5

Step-by-step explanation:

Range = highest value - lowest value

The highest value from the data set given = 1

The lowest value = -4

Therefore :

Range = 1 - (-4)

Range = 1 + 4

Range = 5

3 0
3 years ago
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