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2 years ago

Solve each inequality and graph its solution .. 40 points and brainlyest will be awarded

Mathematics

1 answer:

OLga [1]2 years ago

5 0

Answer:

sorry but i really need

points

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Colton wrote a ratio comparing the number of sports video games that he owns to the number of driving video games that he owns a

nordsb [41]

D. If you were to say the given ratio aloud, it would go something like this: 4 to 3, 4,3 or 4 sports video games to 3 driving ones. So, the answer is 4 to 3, or answer D.

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3 years ago

A box of crackers is 16 cm long, 6 cm wide, and 23 cm tall. What is the volume of this box?

zaharov [31]

Given: 16cm long, 6cm wide, 23 cm tall
Asked: volume of the box
Formula: V=LxWxH
Solution: V = 16x6x23 = n
Answer: 2,208 cm³ volume of the box

6 0

3 years ago

Read 2 more answers

Identify the percent increase or decrease for exponential growth if: y = 5^x

sdas [7]

Answer: 500%

Step-by-step explanation:

It is growing because the base is greater than 1 and the exponent has a positive sign

4 0

3 years ago

If y=24 when x=21, find y when x is 18

ludmilkaskok [199]

Answer:20.571

Step-by-step explanation:

x:y = 21: 24=7:8

8x=7y

y=8x/7

When x=18

y=8*18/7

y=20.571

5 0

3 years ago

There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is

shusha [124]

Answer:

The probability that he picked 2 purpled socks is 0.33.

Step-by-step explanation:

Given:

Number of purple socks, $n(P) = 6$

Number of orange socks, $n(O) = 4$

Two socks are picked without replacement.

Now, total number of socks, $n(T)=N(P)+n(O)=6+4=10$

Probability of picking the first cap as purple cap is given as:

$P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}$

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

$P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}$

Now, probability that both the picked caps are purple is given by their probability product. This gives,

$P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33$

Therefore, the probability that he picked 2 purpled socks is 0.33

4 0

3 years ago