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marusya05 [52]
2 years ago
10

What is the range of possible sizes for side x? _ < x < _

Mathematics
2 answers:
qwelly [4]2 years ago
8 0

Answer:

2.8 < x < 5.8

Step-by-step explanation:

We must apply the Triangle Inequality Theorem which states that for any triangle with sides a, b, and c:

a + b > c

b + c > a

c + a > b

Here, let's arbitrarily denote a as 4.1, b as 1.3, and c as x. So, let's plug these values into the 3 inequalities listed above:

a + b > c  ⇒  4.1 + 1.3 > x  ⇒  5.8 > x

b + c > a  ⇒  1.3 + x > 4.1  ⇒  x > 2.8

c + a > b  ⇒  x + 4.1 > 1.3  ⇒  x > -2.8

Look at the last two: clearly if x is greater than 2.8 (from the second one), then it will definitely be greater than -2.8 (from the third), so we can just disregard the last inequality.

Thus, the range of possible sizes for x are:

2.8 < x < 5.8

<em>~ an aesthetics lover</em>

zysi [14]2 years ago
8 0

Answer:

There are two cases: either x is the largest value or 4.1 is the largest value.

First case: x is largest so that means x < 4.1 + 1.3 which becomes x < 5.8

Second case: 4.1 is largest so that means x + 1.3 > 4.1 which becomes x > 2.8

Answer is 2.8 < x < 5.8.

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Step-by-step explanation:

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Answer:

\dfrac{1}{4}

Step-by-step explanation:

Total number of cards in a standard deck = 52

Number of hearts in the deck = 13

Number of clubs in the deck = 13

Number of diamonds in the deck = 13

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And the cards are not replaced.

Therefore, now cards remaining in each suit:

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Remaining number of diamonds in the deck = 12

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Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Here, number of favorable cases are 12 (i.e. number of hearts)

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Therefore, the required probability is:

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