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3 years ago

Find the total surface area of the prism. 13 in. 9 in. 15 in. Need asap

Mathematics

2 answers:

valkas [14]3 years ago

4 0

wait plsss- i messed up.

natta225 [31]3 years ago

3 0

Answer:

The surface area of a rectangular prism with length of

15, a width of 9 and a height of 13 is:

894.0000 square units.

not sure

Step-by-step explanation:

To find the surface area, use this rectangular prism surface area

formula:

Surface Area =

[(Length x Width) + (Length x Height) + (Width x Height)] x 2

Example: The surface area of a rectangular prism with length of

3 inches, width of 4 inches, and height of 5 inches:

Surface Area = [(3 x 4) + (3 x 5) + (4 x 5)] x 2

Calculated out this gives a surface area of 94 Square Inches.

(not the answer example)

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Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

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3 years ago

Graphing Natural Exponential Functions In Exercise, sketch the graph of the function.

strojnjashka [21]

Answer:

Step-by-step explanation:

Graph: f(x) = 1 - ex

You meant f(x) = 1 - e^x, where ^ represents exponentiation.

First, graph the parent function y = e^x. The y-intercept of this graph is (0, 1), and the x-axis is the horizontal intercept. The graph begins on the left in Quadrant 2 and continues upward in Quadrant 1.

Next, reflect this graph in the x-axis, due to the - sign in f(x) = 1 - e^x. The y-intercept is (0, -1) and the horizontal asymptote is the x-axis.

Finally, translate the whole graph upward by 1 unit.

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3 years ago

X is less than or equal to -5

erma4kov [3.2K]

Answer:

x<=-5

Step-by-step explanation:

6 0

3 years ago

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