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yKpoI14uk [10]
3 years ago
10

Solve for x and write your answer in simplest form: -(6/5x + 6) + 2 = -4/5(-5x + 7)

Mathematics
2 answers:
rodikova [14]3 years ago
7 0

For this case we must find the value of x of the following equation:

- (\frac {6} {5} x + 6) +2 = - \frac {4} {5} (- 5x + 7)

We eliminate the parentheses taking into account that:

- * + = -\\- * - = +\\- \frac {6} {5} x-6 + 2 = 4x- \frac {28} {5}

We simplify the left side:

- \frac {6} {5} x-4 = 4x- \frac {28} {5}

Add \frac {28} {5} to both sides:

- \frac {6} {5} x-4 + \frac {28} {5} = 4x

Add \frac {6} {5} x to both sides:

-4+ \frac {28} {5} = 4x + \frac {6} {5} x\\\frac {-20 + 28} {5} =  \frac {20x + 6x} {5}\\8 = 26x\\x = \frac {8} {26}\\x = \frac {4} {13}

Answer:

x = \frac {4} {13}

julia-pushkina [17]3 years ago
3 0

Answer:

4/13

Step-by-step explanation:

-6/5x - 6 + 2=4x - 28/5

-6/5x - 4=4x - 28/5

-6/5x - 4x= -28/5 + 4  (multiply each side by 5)

-6x - 20x= -28+20

-26x= -8 (divide each side by 26)

-x= -8/26 (multiply each side by -1)

x= 8/26 (reduce)

x= 4/13

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3 years ago
The sum of two numbers is 8, and the sum of their squares is 34. what is the larger number
bija089 [108]

Answer:

The larger number is 5.

Step-by-step explanation:

Let the numbers be represented by x and y.  Then:

x + y = 8   is their sum, and

x² + y² = 34 is the sum of their squares.

Let's solve this system of equations using substitution.  Since x + y = 8,

x = 8 - y.  Subbing this 8 - y for x into the second equation, we get:

(8 - y)² + y² = 34, or

64 - 16 y + y² + y² = 34

Simplifying, we get first: 30 - 16y + 2y² = 0, and then:

2y² - 16y + 30 = 0, and after reducing, y² - 8y + 15 = 0.

This factors into (y - 3)(y - 5) = 0, and so y = 3 and y = 5.

The larger number is 5.

6 0
4 years ago
Rectangle RSUT has diagonals that meet at point x.
Stels [109]

Answer:

x=12.5

y=10

Step-by-step explanation:

Properties of rectangle:

  • Opposite sides are congruent
  • All angles are right angles
  • Diagonals bisect each other
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so from the properties we came to know that diagonals bisects each other and diagonals are of equal length  

Given Rectangle RSUT has diagonals that meet at point X.

⇒RX=SX=UX=TX=\frac{1}{2}RU=\frac{1}{2}ST

⇒RX=\frac{1}{2}ST

⇒4x=\frac{1}{2}(100)

⇒x=12.5

Also XU=RX

⇒(4)(12.5)=5y

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3 years ago
Given the lengths of two sides of a triangle, find the range for the length of the third side. Write an inequality.
djverab [1.8K]

Answer:

| a - b | < length of third side < a + b

Step-by-step explanation:

Visualize the two given sides of the triangle (let's call then a and b), joined at the vertex of the triangle, and forming an angle. We can join the other free end of these two segments, with another segment whose length would vary according to how tiny or large the angle is. We can spread the aperture of the angle they form as much as we can just below  (not reaching this angle measure, because in such case, there will be no triangle of tangible area. In such case, the length of the joining segment will be limited by the addition of the two sides:

length of third side < a + b

In the case the aperture of the angle formed by the two given sides is diminished as much as possible to still form a measurable triangle, the angle has to be just larger than zero, and in such case, the segment joining the other to ends of a and b would be just larger than the absolute value of the difference between a and b:

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These are the two extreme cases, and the length of the third side must be within these limits.

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Novosadov [1.4K]

Answer:

n=14/5

Step-by-step explanation:

4n+n-16=-2

We move all terms to the left:

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We add all the numbers together, and all the variables

5n-14=0

We move all terms containing n to the left, all other terms to the right

5n=14

n=14/5

4 0
3 years ago
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