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damaskus [11]
3 years ago
13

The vertices of AABC are A(-4,5), B(-2,3), and C(-3,3). If AABC is reflected across the line y = 1 to produce the image AA'B'C',

find the coordinates of the vertex
C'
The coordinates of C' after a reflection across the line y = 1 are 1
(Type an ordered pair)

Mathematics
1 answer:
labwork [276]3 years ago
8 0

The distances of the preimage and the image from the line of reflection are equal

The coordinates of C' after a reflection across the line y = 1 are (-3, -1)

The reason the above value is correct is as follows:

The given vertices of the ΔABC are; A(-4, 5), B(-2, 3) and C(-3, 3)

The line of reflection to produce the image ΔA'B'C' is the line y = 1

Required:

To find the coordinates of C' after a reflection across the line y = 1

Solution:

Let (x, y) represent the coordinate of the point C

x-coordinate value:

The line y = 1 is parallel to the x-axis, therefore, the x-value will remain the same following a reflection across the x-axis

Taking the point C' as the image of the corresponding point C(-3, 3), we have that the x-coordinate of the point C' is also -3

<u>x =</u><u> -3</u>

<u />

y-coordinate value:

The difference between the coordinate of the preimage and the reflecting line is the same as the difference between the reflecting line and the coordinates of the image

The y-value distance of the point C(-3, 3), from the line <em>y</em> = 1 is 3 - 1 = 2

Therefore, the y-value  distance of C' from the reflecting line is given as follows;

1 - y = 2

y = 1 - 2 = -1

y = -1

Therefore, the coordinates of the point C' is (x, y) = (<u>-3</u>, <u>-1</u>)

Learn more about reflection transformation here:

brainly.com/question/24306284

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Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)
jeyben [28]

Answer:

The vertex: (\frac{3}{4},-\frac{41}{4} )

The vertical intercept is: y=-8

The coordinates of the two intercepts of the parabola are (\frac{3+\sqrt{41} }{4} , 0) and (\frac{3-\sqrt{41} }{4} , 0)

Step-by-step explanation:

To find the vertex of the parabola 4x^2-6x-8 you need to:

1. Find the coefficients <em>a</em>, <em>b</em>, and <em>c </em>of the parabola equation

<em>a=4, b=-6, \:and \:c=-8</em>

2. You can apply this formula to find x-coordinate of the vertex

x=-\frac{b}{2a}, so

x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex (f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c)

f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\\f(\frac{3}{4})=4\cdot (\frac{3}{4})^2-6\cdot (\frac{3}{4})-8\\y=\frac{-41}{4}

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

f(x)=4x^2-6x-8\\f(0)=4(0)^2-6\cdot 0-0\\f(0)=-8

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square

\mathrm{Add\:}8\mathrm{\:to\:both\:sides}

x^2-6x-8+8=0+8

\mathrm{Simplify}

4x^2-6x=8

\mathrm{Divide\:both\:sides\:by\:}4

\frac{4x^2-6x}{4}=\frac{8}{4}\\x^2-\frac{3x}{2}=2

\mathrm{Write\:equation\:in\:the\:form:\:\:}x^2+2ax+a^2=\left(x+a\right)^2

x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=2+\left(-\frac{3}{4}\right)^2\\x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{41}{16}

\left(x-\frac{3}{4}\right)^2=\frac{41}{16}

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

x_1=\frac{\sqrt{41}+3}{4},\:x_2=\frac{-\sqrt{41}+3}{4}

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MakcuM [25]

Answer:

formula= (kx,ky)

where k = scale factor

= A((8,-4)

= A= (8×12,-4×12)

<u>A= (96,-48)</u>

B= (2,2)

= (2×12,2×12)

<u>B= (24,24)</u>

C= (0,-6)

= (0×12,-6×12)

<u>C= (0,-72)</u>

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Answer:

Check Explanation and the attached image.

Step-by-step explanation:

The histogram of the set of data presented is presented in the attached image to.this solution

The histogram represents data by indicating the frequency of distribution on the y-axis and the sets of variables indicated on the x-axis.

With the constellations named numbers 0 to 6, the frequency of each constellation, that is, the number of stars in each constellation corresponds to the height of the bar representing each constellation.

Hope this Helps!!!

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Answer: True

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22.5 = 15 + 7.5

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