Answer:
Width is 11 inches
Step-by-step explanation:
I am not sure what the question is. I think you might be looking for the width length. The perimeter is the distance around a rectangle. If the whole distance around is 48. We have 2 lengths and 2 widths. They tell us that the length is 13. We have two lengths so the lengths add up to 26. We can subtract that from 48 and that leaves us with 22 (48-26) This is the total for the 2 widths. Since the 2 widths are the same length we divide that number by 2 to get 11.
11 + 11+ 13 + 13 = 48
Answer:
y = (1/4)x - 3
Step-by-step explanation:
The slope-intercept form is y = mx + b. Here we are told that the line passes through (-8, -5) and that its slope is 1/4 (is that correct?).
Substituting -5 for y, -8 for x and 1/4 for m, we get an equation for the y-intercept, b:
-5 = (1/4)(-8) + b, or
-5 = -2 + b, so b = -3, and the desired equation is
y = (1/4)x - 3
23/27 because 46/54 diveded by 2 equals 23/27 which can not be simplified any further
Zero pairs are generated by combining the EQUAL number of positive and negative numbers .
A zero pair could be -11 + 11
Answer:
(a) The expected number of guests until the next one pays by American Express credit card is 4.
(b) The probability that the first guest to use an American Express is within the first 10 to checkout is 0.0215.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of guests until the next one pays by American Express credit card
The probability that a guest paying by American Express credit card is, <em>p</em> = 0.20.
The random variable <em>X</em> follows a Geometric distribution since it is defined as the number of trials before the first success.
The probability mass function of <em>X</em> is:

(a)
The expected value of a Geometric distribution is:

Compute the expected number of guests until the next one pays by American Express credit card as follows:



Thus, the expected number of guests until the next one pays by American Express credit card is 4.
(b)
Compute the probability that the first guest to use an American Express is within the first 10 to checkout as follows:


Thus, the probability that the first guest to use an American Express is within the first 10 to checkout is 0.0215.