Answer:
1.282, -0.5244,...
Step-by-step explanation:
We know that Z is a standard normal variate with mean =0, and std dev =1
a) z-score separates the highest 10% from the rest of the scores
= 90th percentile = 1.282
b) z-score separates the lowest 30% from the rest of the scores
= 30th percentile = -0.5244
c) z-score separates the lowest 40% from the rest of the scores
= 40th percentile = -0.2533
d) z-score separates the lowest 20% from the rest of the score
=20th percentile = -0.8416
To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
Answer:
hmm bro it's kinda blurry can u retake the pic? i will help u to solve it
With two employee shifts, each will work 12 hours (2 x 12)
With three employee shifts, each will work 8 hours (3 x 8)
With four employee shifts, each will work 6 hours (4 x 6)
With six employee shifts, each will work 4 hours ( 6 x 4)
With twelve employees shifts, each will work 2 hours ( 12 x 2)
Answer:
The answer is 73.8
Step-by-step explanation:
Just multiply 12.30 by 6 5 friends and olly
