Answer:
im sorry there is not enough info to answer this question
Step-by-step explanation:
Given:
Two endpoints of a diameter of a circle:
P (-7, -10)
Q (3, 2)
a) To find the center of the circle, find the midpoint of the two points:
midpoint:
(x2 - x1 )/ 2 , (y2 - y1) / 2
x= (2 - (-7))/2 = 4.5
y= (3 - (-10))/2 = 6.5
Therefore, the center of the circle is at C(4.5, 6.5)
b) To find the radius of the circle, we need to find the distance between the two points and divide by 2.
d = √(y2-y1)^2 + (x2 - x1)^2
d = √(2-(-7))^2 + (3 - (-10))^2
d = 5√10 = diameter
r = d/2 = 5√10 /2
Answer:
Add
11 over 2
11 2 + 11 over 4 11 4 = 33 over 4 33 4
Step 1 of 2: Add. Show the work
Step 2 of 2: Simplify.
Simplify
33 over 4 33 4 = 8 and 1 over 48
1
4
Step-by-step explanation:
He is 38 kg.
I'll use only the first letters of their names, to make it simpler:
S+L=54.75
S+M=105
M=4L
S+4L=105
105-54.75=4L-L=3L
L=50.25/3=16.75
S=54.75-16.75=38
Answer:
The equation of the line is, y = x
Step-by-step explanation:
The constraints of the required linear equation are;
The point through which the line passes = (2, 2)
The line to which the required line is parallel = y = x + 4
Two lines are parallel if they have the same slope, therefore, we have;
The slope of the line, y = x + 4 is m = 1
Therefore, the slope of the required line = 1
The equation of the required lime in point and slope form becomes;
y - 2 = 1 × (x - 2)
∴ y = x - 2 + 2 = x
The equation of the required line is therefore, y = x
