All categories

2 years ago

For which function is the domain -5 ≤ x ≤ -1 not appropriate? y = √3x y = 3x y = 3x y = x3

1 answer:

4 0

There is no real values for the square root of a negative value, therefore that negative domain does not exist for the function y=√(3x).

You might be interested in

Which of the following is not a similarity transformation?

Degger [83]

I think its shear, because that is the only one in which the shape actually changes shape and size

7 0

2 years ago

Read 2 more answers

Answer to 24 pls and thanks :D ik its super simple but im not very good at this and i forgot how to do it, and you guys get like

iogann1982 [59]

There is no picture given for us to answer the question!

8 0

3 years ago

To which graph does the point (8,-2) belong ?

Aloiza [94]

It belongs on a coordinate plane

6 0

2 years ago

Read 2 more answers

Write the ratio as a fraction: 630kilometers in 5hours. Simplify your answer.<br><br> ___ km/hour

Bad White [126]

Answer:

126/1=126

Step-by-step explanation:

630:5 as a fraction would be 630/5.

630/5 simplified would be 126/1.

Hope this helps :)

6 0

2 years ago

Read 2 more answers

Which of the following correctly describes the domain of the function shown

labwork [276]

Option D:

$\{x: x \neq 1\}$ is the domain of the function.

Solution:

Given function is

$$r(x)=\frac{2 x}{x-1}$

<u>To find the domain of the function:</u>

Option A: $\{x: x \neq 0\}$

Substitute x = 0 in r(x).

$$r(0)=\frac{2 \times 0}{0-1}=0$

If x = 0, then r(0) = 0

So that x ≠ 0 is false.

So, $\{x: x \neq 0\}$ is not the domain of the function.

Option B: $\{x: x \neq \pm 1\}$

Substitute x = –1 in r(x).

$$r(-1)=\frac{2 \times (-1)}{-1-1}=1$

If x = –1, then r(–1) = 1

So that x = ± 1 is false.

So, $\{x: x \neq \pm 1\}$ is not the domain of the function.

Option C: $\{x: \text { all real numbers }\}$

Substitute x = 1 in r(x).

$$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}$

It is indeterminate.

So, all real numbers are not the domain of the function.

Option D: $\{x: x \neq 1\}$

Substitute x = 1 in r(x).

$$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}$

It is indeterminate.

So, $\{x: x \neq 1\}$ is the domain of the function.

4 0

2 years ago